Which of the following inequalities have no solution?

I recently scraped the overhang at a fast food resterant causing damage that appeared very minor while driving a Uhaul rented my

Sauron [17]

I think that you are reliable

3 0

3 years ago

The function f(x) is a quadratic function and a limited table of values is provided below. Write the equation of the quadratic p

OverLord2011 [107]

Answer:

f(x) = 3x^2 -21x +36

Step-by-step explanation:

The table gives the x- and y-intercepts, which are sufficient to write the equation in factored form. The x-intercepts of 3 and 4 tell you that factors are (x -3)(x -4). When x=0, this product is (-3)(-4) = 12, but the y-intercept value is 3 times that: 36. So, the factored equation is ...

f(x) = 3(x -3)(x -4)

Multiplying this out, we get ...

f(x) = 3(x^2 -7x +12)

f(x) = 3x^2 -21x +36

4 0

3 years ago

7)

Nana76 [90]

Answer:

The answer is c.) 5(2)+2(6-3)

Step-by-step explanation:

This is an addition problem, because you are solving for the multiplied numbers added together.

5(2)+ 2(6-3)

10+(12-6)

10+6

= 16 I hope this help :)

4 0

3 years ago

An architect planned to construct two similar stone pyramid structures in a park. The

kondaur [170]

Answer:

1) Change the length of side AB to 2 feet

Step-by-step explanation:

Given that both structures are similar, it follows that the ratio of their corresponding lengths are equal.

To find out what should be the correct length of AB that she should change to, set up the proportion showing the ratio of 2 corresponding lengths of both structures. Thus:

$\frac{PR}{AC} = \frac{PQ}{AB}$

We will assume AB is unknown.

PR = 7.5 ft

AC = 2.5 ft

PQ = 6 ft

Plug in the values into the equation

$\frac{7.5}{2.5} = \frac{6}{AB}$

Cross multiply

$AB*7.5 = 6*2.5$

$AB*7.5 = 15$

Divide both sides by 7.5

$AB = 2$

The architect should change the length of AB to 2 ft

7 0

2 years ago

Read 2 more answers

Liana's class was going on a very exciting school trip, but when Liana got to school, the school bus had already left! Frantic,

Llana [10]

Answer:

<u>They can catch up with the bus at 10:40 am.</u>

Explanation:

1. Set the time when Liana and her mother can leave (8:40 am) as t₀ = 0; thus the time of driving for them will be t.

2. The average speed at whic Liana's mother drive: 60 miles/hour

3. Thus, the distance they will have driven will be:

distance = average speed × time = 60t

4. The time the bus left was 8:00 am, which is 40 minutes before Liana and her mom can leave.

Thus, the time wil have driven when Liana and her mom have driven t hours minutes will be: t + 40 min / 60 min/ hour = t + 2/3

5. The average speed of teh bus is 45 miles / hour

6. The distance the bus will have driven will be:

distance = average speed × time = 45(t + 2/3)

7. When Liana and her mother catch up with the bus, the distances driven by both of them are equal:

60t = 45(t + 2/3)

60t = 45t + 30

60t - 45t = 30

15t = 30

t = 30/15 = 2

Thus, Liana and her mom can catch up with the bus after 2 hours, since 8:40 am; this is, 10:40 am.

5 0

3 years ago