Answer:
11 and 22
Step-by-step explanation:
We can say that BC=2AC.
Since AB=33, AC=11 and BC=22.
There are 6! = 720 ways of arranging the lamps.
If the leftmost lamp is red, there are 3 choices of lamp in the leftmost position, and the remaining 5 can be placed in any order, so there are 3×5! = 360 ways of arranging the lamps and the leftmost is red.
Hence there is a 360/720 = 1/2 probability that the leftmost lamp is red.
Ignoring lamp color for the moment, the probability of arranging 3 lit lamps and 3 unlit lamps is the same, 1/2.
Since Ryan arranges the lamps randomly by color, then turns 3 of them on randomly, the two events are independent. So
P(leftmost red AND leftmost lit) = P(red) × P(lit) = 1/2² = 1/4
The number of people who bought £4 tickets are 139.
<h3>How to illustrate the equation?</h3>
Let £4 tickets be x
Let £5 tickets be y.
Therefore based on the information given, this will be:
x + y = 223 ..... i
4x + 5y = 936 ..... ii
From equation i
x = 213 - y
Put this into equation ii
4x + 5y = 936
4(213 - y) + 5y = 936
852 - 4y + 5y = 936
Collect like terms
y = 84
This implies that the number of £5 tickets is 84.
Recall that x + y = 223
x + 84 = 223
x = 223 - 84
x = 139
The number of £4 tickets is 139
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Part A:
I have attached the graph of this system of inequalities.
Part B:
Plug in (8,10) into both equations
10 > 3(8) + 10
10 > 24 + 10
10 > 34
This is false!
10 < (-3/4)(8) - 1
10 < (-3)(2) - 1
10 < -6 - 1
10 < -7
This is also false!
So,
(8,10) is not included in the solution area for the system.
54 because i got that a b and dc equal 6 and ad and bc equal 9
