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makvit [3.9K]
3 years ago
5

Alan takes classes at both Westside Community College and Pinewood Community College. At Westside, class fees are $98 per credit

hour, and at Pinewood, class fees are $115 per credit hour. Alan is taking a combined total of 19 credit hours at the two schools.
Suppose that he is taking w credit hours at Westside. Write an expression for the combined total dollar amount he paid for his class fees.

Total he payed (in dolllars) = ?
Mathematics
2 answers:
hammer [34]3 years ago
5 0

<u>Answer:</u>

98 × w + $115(19-w)

<u>Step-by-step explanation:</u>

We are given that Alan takes classes at both Westside Community College, where class fees are $98 per credit hour, and Pinewood Community College, where class fees are $115 per credit hour.

If Alan is taking a total of 19 credit hours at the two mentioned schools, we are to write an expression for the combined total dollar amount he paid for his class fees.

Considering the fees per credit hour mentioned for each school, we can write the total payed fees as:

98 \times w + $115(19-w)

uranmaximum [27]3 years ago
3 0

Answer:

Step-by-step explanation: If w is hours at Westside, then (18-w) is the number of hours taken at Pinewood.

Cost to westside = 98w. Cost to Pinewood = 115(18-w).

Total cost = 98w + 115(18 - w) = 2070 - 17w.

[I guess there should be some constraints like 0 > w > 18]

I put it as "greater than" rather than "greater than or equal" because the problem states he takes classes at both schools, hence he has to take at least something at Westside, and similarly he has to take something at Pinewood so he would not take all 18 hours at Westside.

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Paul is two years younger than Patricia. Daniel is 25% older than Patricia. Ten years ago, Daniel was 50% older than Patricia. H
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We have 3 people: Paul, Daniel and Patricia. Let each name denote that person’s current age in years. Remember that % is the symbol for 1/100.


PAUL: (#A) Paul = Patricia – 2
DANIEL: 
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(#C) Ten years ago, Daniel’s age at that time would have been Daniel’s current age – 10. IE “Daniel – 10”.
Ten years ago, Patricia’s age at that time would have been Patricia’s current age – 10. IE “Patricia – 10”. 
Ten years ago, Daniel’s age at that time (IE Daniel – 10) was 50% greater than Patricia’s age at the time (Patricia – 10). 
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Daniel – 10 = 150% * (Patricia – 10)
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Daniel – 10 = 1.50 * Patricia – 1.50 * 10
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Daniel = 1.50 * Patricia – 5


So now we have 3 equations in 3 unknowns:
(A) Paul = Patricia – 2
(B) Daniel = 1.25 * Patricia
(C) Daniel = 1.50 * Patricia – 5


Solve equations B & C simultaneously
 1.25 * Patricia = 1.50 * Patricia – 5
 1.25 * Patricia – 1.50 * Patricia = – 5
– 0.25 * Patricia = – 5
 Patricia = (– 5) / (– 0.25) 
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So now we can write the 3 people’s ages:
(a) Patricia = 20
(b) Paul = Patricia – 2 = 20 – 2 = 18
(c) Daniel = 1.25 * Patricia = 1.25 * 20 = 25

<span>
</span>

<span>Finally, we check our solution against the original question. </span>
Paul is two years younger than Patricia. ……… 20 – 2 = 18 ✔
Daniel is 25% older than Patricia. ……… 25 = 125% * 20 ✔
Ten years ago, Daniel was 50% older than Patricia. 25 – 10 = 150% (20– 10) ✔


Hope that helped :)

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