Answer:
Infinite pairs of numbers
1 and -1
8 and -8
Step-by-step explanation:
Let x³ and y³ be any two real numbers. If the sum of their cube roots is zero, then the following must be true:
![\sqrt[3]{x^3}+ \sqrt[3]{y^3}=0\\ \sqrt[3]{x^3}=- \sqrt[3]{y^3}\\x=-y](https://tex.z-dn.net/?f=%5Csqrt%5B3%5D%7Bx%5E3%7D%2B%20%5Csqrt%5B3%5D%7By%5E3%7D%3D0%5C%5C%20%5Csqrt%5B3%5D%7Bx%5E3%7D%3D-%20%5Csqrt%5B3%5D%7By%5E3%7D%5C%5Cx%3D-y)
Therefore, any pair of numbers with same absolute value but different signs fit the description, which means that there are infinite pairs of possible numbers.
Examples: 1 and -1; 8 and -8; 27 and -27.
We have that
x²<span>-20x
</span><span>Group
terms that contain the same variable
</span>(x²-20x)
Complete
the square
(x²-20x+10²)------> (x-10)²
the answer is
the number must be 100
Answer:
About 260 seconds
Step-by-step explanation:
Tha rate is:
A: 8L/1.66666m
b: 10L/1m (converted to litres)
Divide 2400 by those rates above which:
2400 / (8/1.66666) = 500
2400 / (10/1) = 240
500 - 240 = 260
The answer is nine hope this helps :)
Number 9 is no because if you were to divide that it be a decimal and a decimal is an irrational number.
Number 10 is yes. When divide 2 by 5 you get 0.4 which is a terminating number because it never ends