4 years ago

What is compatible to 428

Mathematics

1 answer:

kakasveta [241]4 years ago

7 0

Any number but 0 is compatible because you can add any number to 428.

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The cost for children under twelve at a certain buffet restaurant is a base charge of a dollar plus twenty-five cents for each y

Nady [450]

Answer:

$Cost = 1 + 0.25y$

$Cost =3.25$

Step-by-step explanation:

Given

$Base\ Amount = \$ 1$

$Additional = 25cents$ of child's age

Solving (1):

Determine the cost function.

Represent the years as y.

So, we have:

$Additional = 25cents$ * y

Convert 25 cents to dollars.

$25 cents = 25 * \$0.01$

$25 cents = \$0.25$

So, we have:

$Additional = \$0.25 * y$

The cost amount is then:

$Cost = Base\ Amount + Additional$

$Cost = 1 + 0.25y$ --- This is the cost function

Solving (b): Cost of 9 years old.

In this case;

$y = 9$

Substitute 9 for y in $Cost = 1 + 0.25y$

$Cost =1 + 0.25 * 9$

$Cost =1 + 2.25$

$Cost =3.25$ --- This is the cost for a child of 9

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4 years ago

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Gemiola [76]

N=20

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Answer:

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Step-by-step explanation:

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Step-by-step explanation:

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Step-by-step explanation:

|-6| = 6

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