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JulsSmile [24]
4 years ago
7

What is compatible to 428

Mathematics
1 answer:
kakasveta [241]4 years ago
7 0
Any number but 0 is compatible because you can add any number to 428.
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The cost for children under twelve at a certain buffet restaurant is a base charge of a dollar plus twenty-five cents for each y
Nady [450]

Answer:

Cost = 1 + 0.25y

Cost =3.25

Step-by-step explanation:

Given

Base\ Amount = \$ 1

Additional = 25cents of child's age

Solving (1):

Determine the cost function.

Represent the years as y.

So, we have:

Additional = 25cents * y

Convert 25 cents to dollars.

25 cents = 25 * \$0.01

25 cents = \$0.25

So, we have:

Additional = \$0.25 * y

The cost amount is then:

Cost = Base\ Amount + Additional

Cost = 1 + 0.25y --- This is the cost function

Solving (b): Cost of 9 years old.

In this case;

y = 9

Substitute 9 for y in Cost = 1 + 0.25y

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Cost =1 + 2.25

Cost =3.25 --- This is the cost for a child of 9

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Gemiola [76]
N=20




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Dmitry_Shevchenko [17]

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Step-by-step explanation:

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A is what percent of B? c A = 10 km, B = 1 km
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Step-by-step explanation:

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|-6| = 6

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8 0
3 years ago
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