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Citrus2011 [14]
3 years ago
6

1. y=3x+6 2. y=-2x+4 3. y=1/2x-6 4. y=2/3x 5. y=-4x+1/8​

Mathematics
1 answer:
bekas [8.4K]3 years ago
3 0

Answer:

Here u go bro. You have to just replace y and x with zero and then draw the I think structure say say:')

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Unit rate feet per second 180 miles over 2 hours
Tatiana [17]
So that is equal to 180 miles per 2 hours which is 90 miles per hour if each hour has the same m/hr rate.
You can set up a proportion:
let x = number of miles per hour
\frac{x}{180} = \frac{1}{2}
cross multiply and you get
2x=180
divide both sides by 2 and you get
x=90
so you get the same answer both ways,
90 miles per hour
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Factor completely 5x2 − 5x − 100.
Rama09 [41]
First, factor out 5:
5 (x² -x -20)
We need two numbers that add to -1 and multiply to -20. -5 and 4 satisfy this.
5(x-5)(x+4)
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What is the area of the prism shown below?<br> prism<br> 10 in.<br> 8 in.<br> 11 in.
Gnom [1K]

Answer:

1180

Step-by-step explanation:

10* 8*11

you times all the figures to give you the right answer that is 1180

5 0
1 year ago
What is the equation of circle whose centre is (0,0) and radius'r' ?​
adoni [48]

Answer:

On the right is a circle with centre (0, 0), radius r and (x, y) any point on the circle. Distance between (0,0) and (x, y) equals the radius, r. If the centre is (0, 0), the equation of the circle will be of the form x2 + y2 = r2.

4 0
3 years ago
Find the smallest positive $n$ such that \begin{align*} n &amp;\equiv 3 \pmod{4}, \\ n &amp;\equiv 2 \pmod{5}, \\ n &amp;\equiv
Alex777 [14]

4, 5, and 7 are mutually coprime, so you can use the Chinese remainder theorem right away.

We construct a number x such that taking it mod 4, 5, and 7 leaves the desired remainders:

x=3\cdot5\cdot7+4\cdot2\cdot7+4\cdot5\cdot6

  • Taken mod 4, the last two terms vanish and we have

x\equiv3\cdot5\cdot7\equiv105\equiv1\pmod4

so we multiply the first term by 3.

  • Taken mod 5, the first and last terms vanish and we have

x\equiv4\cdot2\cdot7\equiv51\equiv1\pmod5

so we multiply the second term by 2.

  • Taken mod 7, the first two terms vanish and we have

x\equiv4\cdot5\cdot6\equiv120\equiv1\pmod7

so we multiply the last term by 7.

Now,

x=3^2\cdot5\cdot7+4\cdot2^2\cdot7+4\cdot5\cdot6^2=1147

By the CRT, the system of congruences has a general solution

n\equiv1147\pmod{4\cdot5\cdot7}\implies\boxed{n\equiv27\pmod{140}}

or all integers 27+140k, k\in\mathbb Z, the least (and positive) of which is 27.

3 0
3 years ago
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