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Vitek1552 [10]
3 years ago
12

The pentagon PORSTis transformed into POR'ST using which two transformations?

Mathematics
1 answer:
Rashid [163]3 years ago
5 0
Hey listen kid I can’t answer your question I’m sorry I am just doing this because I need help with my math sorry
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The value of y varies directly with x. If x = 218, then y = 436. What is
adell [148]

Answer:

<h2>x = 7</h2>

Step-by-step explanation:

To find the value of the value of x when

y = 14 we must first find the relationship between them

The statement

The value of y varies directly with x is written as

y \:  \:  \:  \alpha  \:  \:  \: kx

where k is the constant of proportionality

when x = 218

y = 436

So we have

436 = 218k

Divide both sides by 218

k = 2

So the formula for the variation is

<h2>y = 2x</h2>

when y = 14

We have

14 = 2x

Divide both sides by 2

<h3>x = 7</h3>

Hope this helps you.

5 0
3 years ago
If 400 patrons visit the park in March and 550 patrons visit in April, the total number of patrons who
Zielflug [23.3K]
950 is a real number, and it is a rational number since it can be expressed as 950/1. Therefore, it falls into all of the categories expect irrational numbers.
7 0
3 years ago
Help please!!!!ASAP! Ill give brainliest! And 50pts!<br><br> What is the value of q?
fomenos
It is c hope this helps :)
4 0
3 years ago
Read 2 more answers
What is the value of 10+/-3-6/
garri49 [273]

Answer:

18

Step-by-step explanation:

-3-6= -8 but since its absolute value it'll be 8 so 8 plus 10 = 18

7 0
3 years ago
Calculate two iterations of Newton's Method for the function using the given initial guess. (Round your answers to four decimal
pickupchik [31]

Answer:

The first and second iteration of Newton's Method are 3 and \frac{11}{6}.

Step-by-step explanation:

The Newton's Method is a multi-step numerical method for continuous diffentiable function of the form f(x) = 0 based on the following formula:

x_{i+1} = x_{i} -\frac{f(x_{i})}{f'(x_{i})}

Where:

x_{i} - i-th Approximation, dimensionless.

x_{i+1} - (i+1)-th Approximation, dimensionless.

f(x_{i}) - Function evaluated at i-th Approximation, dimensionless.

f'(x_{i}) - First derivative evaluated at (i+1)-th Approximation, dimensionless.

Let be f(x) = x^{2}-8 and f'(x) = 2\cdot x, the resultant expression is:

x_{i+1} = x_{i} -\frac{x_{i}^{2}-8}{2\cdot x_{i}}

First iteration: (x_{1} = 2)

x_{2} = 2-\frac{2^{2}-8}{2\cdot (2)}

x_{2} = 2 + \frac{4}{4}

x_{2} = 3

Second iteration: (x_{2} = 3)

x_{3} = 3-\frac{3^{2}-8}{2\cdot (3)}

x_{3} = 2 - \frac{1}{6}

x_{3} = \frac{11}{6}

7 0
4 years ago
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