All categories

3 years ago

The pentagon PORSTis transformed into POR'ST using which two transformations?

Mathematics

1 answer:

Rashid [163]3 years ago

5 0

Hey listen kid I can’t answer your question I’m sorry I am just doing this because I need help with my math sorry

You might be interested in

The value of y varies directly with x. If x = 218, then y = 436. What is

adell [148]

Answer:

Step-by-step explanation:

To find the value of the value of x when

y = 14 we must first find the relationship between them

The statement

The value of y varies directly with x is written as

$y \: \: \: \alpha \: \: \: kx$

where k is the constant of proportionality

when x = 218

y = 436

So we have

436 = 218k

Divide both sides by 218

k = 2

So the formula for the variation is

when y = 14

We have

14 = 2x

Divide both sides by 2

Hope this helps you.

5 0

3 years ago

If 400 patrons visit the park in March and 550 patrons visit in April, the total number of patrons who

Zielflug [23.3K]

950 is a real number, and it is a rational number since it can be expressed as 950/1. Therefore, it falls into all of the categories expect irrational numbers.

7 0

3 years ago

Help please!!!!ASAP! Ill give brainliest! And 50pts!<br><br> What is the value of q?

fomenos

It is c hope this helps :)

4 0

3 years ago

Read 2 more answers

What is the value of 10+/-3-6/

garri49 [273]

Answer:

Step-by-step explanation:

-3-6= -8 but since its absolute value it'll be 8 so 8 plus 10 = 18

7 0

3 years ago

Calculate two iterations of Newton's Method for the function using the given initial guess. (Round your answers to four decimal

pickupchik [31]

Answer:

The first and second iteration of Newton's Method are 3 and $\frac{11}{6}$ .

Step-by-step explanation:

The Newton's Method is a multi-step numerical method for continuous diffentiable function of the form $f(x) = 0$ based on the following formula:

$x_{i+1} = x_{i} -\frac{f(x_{i})}{f'(x_{i})}$

Where:

$x_{i}$ - i-th Approximation, dimensionless.

$x_{i+1}$ - (i+1)-th Approximation, dimensionless.

$f(x_{i})$ - Function evaluated at i-th Approximation, dimensionless.

$f'(x_{i})$ - First derivative evaluated at (i+1)-th Approximation, dimensionless.

Let be $f(x) = x^{2}-8$ and $f'(x) = 2\cdot x$ , the resultant expression is:

$x_{i+1} = x_{i} -\frac{x_{i}^{2}-8}{2\cdot x_{i}}$

First iteration: ( $x_{1} = 2$ )

$x_{2} = 2-\frac{2^{2}-8}{2\cdot (2)}$

$x_{2} = 2 + \frac{4}{4}$

$x_{2} = 3$

Second iteration: ( $x_{2} = 3$ )

$x_{3} = 3-\frac{3^{2}-8}{2\cdot (3)}$

$x_{3} = 2 - \frac{1}{6}$

$x_{3} = \frac{11}{6}$

7 0

4 years ago