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3 years ago

Think About the Process Which property of exponents do you use to simplify this expression? Simplify the expression. 12^8/12^4

Mathematics

1 answer:

Naya [18.7K]3 years ago

3 0

Answer:

12^4 = 20736

Step-by-step explanation:

The property of exponents used to simplify : 12^8/12^4

The division property :

a^x / a^y = a^(x - y)

Therefore ;

12^8/12^4

12^8 / 12^4 = 12^(8 - 4) = 12^4 = 20,736

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Solve sin4x cosx-sinx cos4x = sqrt(2)/2 for [0, 2pi)

natita [175]

Answer:

x = π/12, π/4, 3π/4, 11π/12, 17π/12, 19π/12

Step-by-step explanation:

sin(4x) cos x − sin x cos(4x) = √2 / 2

Use angle difference formula.

sin(4x − x) = √2 / 2

sin(3x) = √2 / 2

3x = π/4 + 2kπ, 3π/4 + 2kπ

x = π/12 + 2kπ/3, π/4 + 2kπ/3

x = π/12, π/4, 3π/4, 11π/12, 17π/12, 19π/12

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3 years ago

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Step-by-step explanation:

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2 years ago

Read 2 more answers

PLEASE HELP ME GUYS OR I WONT PASS this calculus!!!!

KonstantinChe [14]

Answer:

b. $\displaystyle \frac{1}{2}$

General Formulas and Concepts:

Pre-Algebra

Order of Operations: BPEMDAS

Brackets
Parenthesis
Exponents
Multiplication
Division
Addition
Subtraction

Left to Right

Algebra I

Functions
Function Notation
Exponential Rule [Rewrite]: $\displaystyle b^{-m} = \frac{1}{b^m}$
Exponential Rule [Root Rewrite]: $\displaystyle \sqrt[n]{x} = x^{\frac{1}{n}}$

Calculus

Derivatives

Derivative Notation

Basic Power Rule:

f(x) = cxⁿ
f’(x) = c·nxⁿ⁻¹

Derivative Rule [Chain Rule]: $\displaystyle \frac{d}{dx}[f(g(x))] =f'(g(x)) \cdot g'(x)$

Step-by-step explanation:

Step 1: Define

Identify

$\displaystyle H(x) = \sqrt[3]{F(x)}$

Step 2: Differentiate

Rewrite function [Exponential Rule - Root Rewrite]: $\displaystyle H(x) = [F(x)]^\bigg{\frac{1}{3}}$
Chain Rule: $\displaystyle H'(x) = \frac{d}{dx} \bigg[ [F(x)]^\bigg{\frac{1}{3}} \bigg] \cdot \frac{d}{dx}[F(x)]$
Basic Power Rule: $\displaystyle H'(x) = \frac{1}{3}[F(x)]^\bigg{\frac{1}{3} - 1} \cdot F'(x)$
Simplify: $\displaystyle H'(x) = \frac{F'(x)}{3}[F(x)]^\bigg{\frac{-2}{3}}$
Rewrite [Exponential Rule - Rewrite]: $\displaystyle H'(x) = \frac{F'(x)}{3[F(x)]^\bigg{\frac{2}{3}}}$

Step 3: Evaluate

Substitute in x [Derivative]: $\displaystyle H'(5) = \frac{F'(5)}{3[F(5)]^\bigg{\frac{2}{3}}}$
Substitute in function values: $\displaystyle H'(5) = \frac{6}{3(8)^\bigg{\frac{2}{3}}}$
Exponents: $\displaystyle H'(5) = \frac{6}{3(4)}$
Multiply: $\displaystyle H'(5) = \frac{6}{12}$
Simplify: $\displaystyle H'(5) = \frac{1}{2}$