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hodyreva [135]
3 years ago
8

Problem:2x+3 (x-4)=x-20

Mathematics
1 answer:
monitta3 years ago
6 0
Let's solve your equation step-by-step.<span><span><span>2x</span>+<span>3<span>(<span>x−4</span>)</span></span></span>=<span>x−20</span></span>Step 1: Simplify both sides of the equation.<span><span><span>2x</span>+<span>3<span>(<span>x−4</span>)</span></span></span>=<span>x−20</span></span><span>Simplify: (Show steps)</span><span><span><span>5x</span>−12</span>=<span>x−20</span></span>Step 2: Subtract x from both sides.<span><span><span><span>5x</span>−12</span>−x</span>=<span><span>x−20</span>−x</span></span><span><span><span>4x</span>−12</span>=<span>−20</span></span>Step 3: Add 12 to both sides.<span><span><span><span>4x</span>−12</span>+12</span>=<span><span>−20</span>+12</span></span><span><span>4x</span>=<span>−8</span></span>Step 4: Divide both sides by 4.<span><span><span>4x/</span>4</span>=<span><span>−8/</span>4</span></span><span>x=<span>−2</span></span>Answer: x=−2
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The common ratio of a geometric series is \dfrac14 4 1 ​ start fraction, 1, divided by, 4, end fraction and the sum of the first
myrzilka [38]

Answer:

The common ratio of a geometric series is \dfrac14

4

1 ​

start fraction, 1, divided by, 4, end fraction and the sum of the first 4 terms is 170

The first term is 128

Step-by-step explanation:

The common ratio of the geometric series is given as:

r =  \frac{1}{4}

The sum of the first 4 term is 170.

The sum of first n terms of a geometric sequence is given b;

s_n=\frac{a_1(1-r^n)}{1-r}

common ratio, n=4 and equate to 170.

\frac{a_1(1-( \frac{1}{4} )^4)}{1- \frac{1}{4} } = 170

\frac{a_1(1- \frac{1}{256} )}{ \frac{3}{4} } = 170\\\\ \frac{255}{256} a_1 = \frac{3}{4}  \times 170\\\\\frac{255}{256} a_1 = \frac{255}{2}  \\\\\frac{1}{256} a_1 = \frac{1}{2}  \\\\ a_1 = \frac{1}{2}   \times 256\\\\a_1 = \frac{1}{2}   \times 256 \\\\= 128

8 0
3 years ago
The solution for x2 + 2x + 8 ≤ 0 is
Marina CMI [18]

Answer:

Please use " ^ " for exponentiation: x^2 + 2x + 8 ≤ 0.

Let's solve this by completing the square:

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(x + 1)^2 + 7 ≤ 0

Taking the sqrt of both sides: (x + 1)^2 = i*sqrt(7)

Then the solutions are x = -1 + i√7 and x = -1 - i√7

There's something really wrong here. I've graphed your function, x^2 + 2x + 8, and can see from the graph that there are no real roots, but only complex roots. Please double-check to ensure that you've copied down this problem correctly.

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Answer:

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Answer:

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Step-by-step explanation:

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