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4 years ago

6

The price of one share of a company at the end of the day Monday was $126.38. The price of of the share Decreased $7.95 the next

day. What was the price of the share at the end of the day Tuesday?

1 answer:

Kaylis [27]4 years ago

6 0

Answer:

$118.43

Step-by-step explanation:

The price on Monday ($126.38), less the decrease ($7.95), results in the price on Tuesday:

$126.38

- 7.95

----------------

$ 118.43

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If mZDCB = 140°, then mZACD = [?]° !!!PLS HELP I WILL MARK BRAINLIEST !!!

Readme [11.4K]

Answer:

40°

Step-by-step explanation:

$m\angle DCB +m\angle ACD = 180\degree$ (Linear pair angles)

$\implies 140\degree +m\angle ACD = 180\degree$

$\implies m\angle ACD = 180\degree-140\degree$

$\implies m\angle ACD = 40\degree$

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2 years ago

Z^5=-243i, find the solution to the equation whose argument is strictly between 180 degrees and 270 degrees. Round your answer t

11Alexandr11 [23.1K]

Answer:

The solution is $z = -2.853 - i 0.927$ .

Step-by-step explanation:

Complex power is determined by means of the De Moivre's Theorem, whose expression is:

$z^{n} = r^{n} \cdot (\cos n\theta + i \sin n\theta)$

Where $r$ is the norm of the complex number. In this case, expression can be written as:

$-i 243 = 3^{5} \cdot (\cos 5\theta + i \sin 5\theta)$

The real component must be equal to zero and complex component must be equal to -1. That is to say:

$\cos 5\theta = 0$

$\sin 5\theta = -1$

Possible solutions for each component are, respectively:

Real component

$5\theta = \cos^{-1}0$

$5\theta = \frac{\pi}{2} \pm \pi\cdot j$ , $\forall j \in \mathbb{N}_{O}$

$\theta = \frac{\pi}{10} \pm \frac{\pi}{5} \cdot j$ , $\forall j \in \mathbb{N}_{O}$

Possible solutions: $\frac{11\pi}{10}$ , $\frac{13\pi}{10}$ , $\frac{3\pi}{2}$

Complex component

$5\theta = \sin^{-1}(-1)$

$5\theta = \frac{3\pi}{2} \pm 2\pi \cdot j$ , $\forall j \in \mathbb{N}_{O}$

$\theta = \frac{3\pi}{10} \pm \frac{2\pi}{5} \cdot j$ , $\forall j \in \mathbb{N}_{O}$

Possible solutions: $\frac{11\pi}{10}$ , $\frac{3\pi}{2}$

There is one solution whose argument is strictly between 180 degrees ( $\pi$ ) and 270 degrees ( $1.5\pi$ ).

$z = 3 \cdot \left( \cos \frac{11\pi}{10} + i \sin \frac{11\pi}{10} \right)$

$z = -2.853 - i 0.927$

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3 years ago

Find th areas and circumference 5 cm 2 cm

mihalych1998 [28]

Answer:

The Area is 10cm, and the perimeter is 14cm

Step-by-step explanation:

Area:

a = w · l 5cm · 2cm =10cm

Perimeter:

p = 2(l+w) 2(5 + 2) = 14

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2 years ago

-3/7 x -2/3<br> BRAINLIEST GETS 15 POINTS!!!<br> A.) -2/7<br> B.) -5/21<br> C.) 5/21<br> D.) 2/7

sveta [45]

Answer:

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Step-by-step explanation:

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3 years ago

If data set A has a smaller standard deviation than data set B, what would be different about their distributions?

Aleksandr-060686 [28]

Answer:

Data set B would have flatter distribution with more data in each tail.

Step-by-step explanation:

We are given the following in the question:

Data set A has a smaller standard deviation than data set B.

$\sigma_A < \sigma_B$

Standard Deviation:

It is a measure of dispersion of data.
It tells us about how much the data deviates around the mean.
It tells us about the overall deviation of the data from the mean.
The standard deviation is small when the data are all close to the mean showing less variation.
The standard deviation is larger when the data values are farther away from the mean, showing more variation.

Since data A has less standard deviation than data B, then data B has a flatter graphical representation as more of the data are present on the tails.

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3 years ago