So remember that area of a rectangle is a = bh. In this case, our sides are 2 and n - 3 (three less than unknown number) and our area is 22. Using our info, we can form the equation: $22=2(n-3)$ . From here we can solve for n.

Firstly, foil 2(n-3): $22=2n-6$

Next, add 6 on both sides of the equation: $28=2n$

Next, divide both sides of the equation and your answer will be 14 = n. In context, the value of the unknown number is 14 in.

8 0

4 years ago

Read 2 more answers

10 points

natulia [17]

The answer would be B

4 0

4 years ago

The first week of January there are 49 dogs and 28 cats in the shelter. Throughout the month the ratio of dogs to cats remains t

Katen [24]

There should be a total of 50 dogs if there’s 29 cats because -

6 0

4 years ago

Please help me . I need help with this. I’m getting very very frustrated !!! You can get 35 points !

Elden [556K]

Notes:

The sign of the coefficient of the quadratic equation determines if the vertex is a minimum or maximum. Positive looks like ∪ so has a minimum. Negative looks like ∩ so has a maximum.
Maximum/minimum height is the y-value of the vertex.
Time to reach maximum height is the x-value of the vertex (which is also the Axis-Of-Symmetry).

Answer: 4) maximum

5) 20.1 ft

6) 2 seconds

<u>Step-by-step explanation:</u>

4) h(t) = -16t² + 256t

↓

the coefficient is negative so it looks like ∩.

Therefore, it has a maximum.

5) h(t) = -16t² + 30t + 6

$\text{AOS: }x=\dfrac{-b}{2a}\quad \rightarrow \quad x=\dfrac{-(30)}{2(-16)}=\dfrac{-30}{-32}=\dfrac{15}{16}\\\\\\\text{Maximum: }h\bigg(\dfrac{15}{16}\bigg)=-16\bigg(\dfrac{15}{16}\bigg)^2+30\bigg(\dfrac{15}{16}\bigg)+6\\\\\\.\qquad \qquad \qquad \qquad =\dfrac{-225}{16}+\dfrac{450}{16}+\dfrac{96}{16}\\\\\\.\qquad \qquad \qquad \qquad =\dfrac{321}{16}\\\\\\.\qquad \qquad \qquad \qquad \approx20.1$

6) h(t)=-16t²+64t+80

$\text{AOS: }x=\dfrac{-b}{2a}\quad \rightarrow \quad x=\dfrac{-(64)}{2(-16)}=\dfrac{-64}{-32}=2$

8 0

3 years ago