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Gennadij [26K]
3 years ago
15

Ricardo is constructing the circumscribed circle for △XYZ. He has already used his compass and straightedge to complete the part

of the construction shown in the figure.
Which construction could be his next step?


Construct the angle bisector of ∠X .

Construct the line through points A and Y.

Construct the perpendicular bisector of YZ¯¯¯¯¯ .

Construct the line through points B and Z.

Mathematics
2 answers:
balu736 [363]3 years ago
7 0
<span>Construct the perpendicular bisector of YZ</span>
Fantom [35]3 years ago
5 0

Answer:

The correct answer is:

<em>Construct the perpendicular bisector of YZ.</em>

Step-by-step explanation:

The steps for the construction of circumscribed circle is:

  • Construct the perpendicular bisector of one side of triangle
  • Construct the perpendicular bisector of another side
  • Where they cross is the center of the Circumscribed circle
  • Place compass on the center point, adjust its length to reach any corner of the triangle, and draw your Circumscribed circle.

Hence, from the given figure first step is already done now we need to proceed to the second step of the construction.

Hence, the statement that best represents the next step in the construction is:

Construct the perpendicular bisector of YZ

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Quick!! I need help with this question!
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Drag and drop formal proof. Prove the Polygon Exterior Angle Sum Theorem for the enclosed triangle, that is ∠1+∠2+∠3=360°
jasenka [17]

Answer:

The sum of all the external angles of a triangle is 360°.

Step-by-step explanation:

Let there are n sides in a polygon.

So, there are n internal angles in the polygon, let ∠i1, ∠i2, ∠i3, ..., ∠in are the measure of n internal angles of the polygon.

The measure of external angle corresponding to ∠i1,  ∠1= 180°-∠i1,

The measure of external angle corresponding to ∠i2, ∠2 = 180°-∠i2,

Similarly, the measure of external angle corresponding to ∠in, ∠n = 180°-∠in.

Now, the sum of all the external angles of the polygon,

(∠1+∠2+...+∠n)=(180°-∠i1)+(180°-∠i2)+...+(180°-∠in)

=(180°+180°+...n times)-(∠i1+∠i2+...+∠in)

=n x 180° - (∠i1+∠i2+...+∠in)

As ∠i1+∠i2+...+∠in is the sum of all the internal angles of the polygon.

So, the sum of all the external angles of the polygon =

(n x 180°) - (sum of all the internal angles of the polygon).

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Therefore, the sum of all the external angles of a triangle,

∠1+∠2+∠3 =3x180°-(∠i1+∠i2+∠i3)

                 =540°=180°

                 =360°.

Hence, the sum of all the external angles of a triangle is 360°.

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3 years ago
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Answer:

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