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Nikitich [7]
2 years ago
10

What is 3x-12=-15? I need to know

Mathematics
1 answer:
cupoosta [38]2 years ago
7 0
3x - 12 = -15

Add 12 on both sides.

-12 + 12 = 0

-15 + 12 = -3

The equation is now 3x = -3.

Divide both sides by 3 to isolate the variable.

3x / 3 = x
-3 / 3 = -1

So, x = -1.
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Answer:

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Step-by-step explanation:

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5 0
3 years ago
What value of x is in the solution set of 2(3x - 1) = 4x - 6?<br> EO<br> -10
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Answer:

D) -1

Step-by-step explanation:

6x-2≥4x-6

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5 0
3 years ago
Read 2 more answers
Please help Cassie uses 1 quart cranberry juice., 1/2 gallon ginger ale, and 1 1/2 pints orange juice to make fruit punch. How m
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3 years ago
One more... and ill be out of yalls hair.
Zarrin [17]
Awnser:69
I had this question a few minutes ago, that’s funny
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2 years ago
Approximate the change in the volume of a sphere when its radius changes from r = 30 ft to r=10.1 ft [v(r)=4/3Ï€r^3]. When r cha
ella [17]

Answer: ∆V for r = 10.1 to 10ft

∆V = 40πft^3 = 125.7ft^3

Approximate the change in the volume of a sphere When r changes from 10 ft to 10.1 ft, ΔV=_________

[v(r)=4/3Ï€r^3].

Step-by-step explanation:

Volume of a sphere is given by;

V = 4/3πr^3

Where r is the radius.

Change in Volume with respect to change in radius of a sphere is given by;

dV/dr = 4πr^2

V'(r) = 4πr^2

V'(10) = 400π

V'(10.1) - V'(10) ~= 0.1(400π) = 40π

Therefore change in Volume from r = 10 to 10.1 is

= 40πft^3

Of by direct substitution

∆V = 4/3π(R^3 - r^3)

Where R = 10.1ft and r = 10ft

∆V = 4/3π(10.1^3 - 10^3)

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And for R = 30ft to r = 10.1ft

∆V = 4/3π(30^3 - 10.1^3)

∆V = 34626.3πft^3

3 0
3 years ago
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