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4 years ago

14

Simplify the expression showing all the steps using correct mathematical notation. If you could write it down and take a picture

that'd be amazing!

1 answer:

zaharov [31]4 years ago

4 0

1+3^2=3^2 which is 3(3), and that equals 9. 9/5= 1.8.

1.8-6=-4.2

-4.2+2= -2.2

You might be interested in

(r3 +6r2 −21r−18)÷(r−3) solve using synthetic division

alexandr402 [8]

Answer:

y = x^2 + 9x + 6 No remainder.

Step-by-step explanation:

The divisor will be 3 The sign on the divisor switches.

3 || 1 + 6 - 21 - 18 ||

3 27 + 18

================================

1 9 6 0

The answser is x^2 + 9x + 6

5 0

4 years ago

Two brands of AAA batteries are tested in order to compare their voltage. The data summary can be found below. Find the 93% conf

kobusy [5.1K]

Answer:

$(\bar X_1 -\bar X_2) \pm z_{\alpha/2} \sqrt{\frac{s^2_1}{n_1}+\frac{s^2_}{n_2}}$

And replacing we got:

$(9.2 -8.8) - 1.811 \sqrt{\frac{0.3^2}{27}+\frac{0.1^2}{30}}= 0.2903$

$(9.2 -8.8) + 1.811 \sqrt{\frac{0.3^2}{27}+\frac{0.1^2}{30}}= 0.5097$

And the confidence interval for the difference of means would be given by:

$0.2903 \leq \mu_1 -\mu_2 \leq 0.5097$

Step-by-step explanation:

Previous concepts

A confidence interval is "a range of values that’s likely to include a population value with a certain degree of confidence. It is often expressed a % whereby a population means lies between an upper and lower interval".

The margin of error is the range of values below and above the sample statistic in a confidence interval.

Normal distribution, is a "probability distribution that is symmetric about the mean, showing that data near the mean are more frequent in occurrence than data far from the mean".

We have the following data given:

$\bar X_1 = 9.2 , \bar X_2 = 8.8, \sigma_1= 0.3, n_1 = 27, \sigma_2 = 0.1, n_2 = 30$

In order to find the critical value we need to take in count that we are finding the interval for a proportion, so on this case we need to use the z distribution. Since our interval is at 93% of confidence, our significance level would be given by $\alpha=1-0.93=0.07$ and $\alpha/2 =0.035$ . And the critical value would be given by:

$z_{\alpha/2}=-1.811, z_{1-\alpha/2}=1.811$

The confidence interval is given by:

$(\bar X_1 -\bar X_2) \pm z_{\alpha/2} \sqrt{\frac{s^2_1}{n_1}+\frac{s^2_}{n_2}}$

And replacing we got:

$(9.2 -8.8) - 1.811 \sqrt{\frac{0.3^2}{27}+\frac{0.1^2}{30}}= 0.2903$

$(9.2 -8.8) + 1.811 \sqrt{\frac{0.3^2}{27}+\frac{0.1^2}{30}}= 0.5097$

And the confidence interval for the difference of means would be given by:

$0.2903 \leq \mu_1 -\mu_2 \leq 0.5097$

4 0

3 years ago

Question number 25, a.

ivann1987 [24]

23
4tfvbnjhgfdcvbnjtfvbjvcbbccbcbcbcb

3 0

3 years ago

<img src="https://tex.z-dn.net/?f=-%5Cfrac%7B1%7D%7B2%7Dx%20-%203%20%3D%20-9" id="TexFormula1" title="-\frac{1}{2}x - 3 = -9" al

Nana76 [90]

The answer is x=12.

8 0

3 years ago

Which can be used to describe the expression? Check all that apply.

Burka [1]

Answer:

B and D

Step-by-step explanation:

One thing is for certain. The final answer will be 1/r^12 or r^(-12)

When written as the given of (r^-4)^3, the powers are multiplied.

The first one is false. There are 4 factors of r^-4 If you get an answer that says it is true, then the question means that r^-4 is 3 equal factors of r^-12

B is true

C: not true. The exponents are multiplied, not added.

D is true

E: not true. This is the same thing as C.

6 0

3 years ago