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frutty [35]
3 years ago
8

Find r(t) if r'(t)=ti+e^tj+te^tk and r(0)=i+j+k

Mathematics
1 answer:
weeeeeb [17]3 years ago
6 0
R(t) = integral of r'(t) = integral of ti + e^tj + te^tk = 1/2t^2i + e^tj + (te^t - e^t)k + c
r(0) = j - k + c = i + j + k
c = i + 2k
Therefore, r(t) = (1/2t^2 + 1)i + e^tj + (te^t - e^t + 2)k
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FrozenT [24]

Answer:

7480 hours

Step-by-step explanation:

440 - 100 = 340

LCM of 440 and 340

440 = 2 × 2 × 2 × 5 × 11

340 = 2 × 2 × 5 × 17

LCM = 2 × 2 × 2 × 5 × 11 × 17

LCM = 7480

4 0
3 years ago
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aev [14]

Answer:

x=4

Step-by-step explanation:

5x-4=16

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8 0
3 years ago
Determine whether the improper integral converges or diverges, and find the value of each that converges.
____ [38]

Answer:

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Step-by-step explanation:

Assuming this integral:

\int_{-\infty}^0 5 e^{60x} dx

We can do this as the first step:

5 \int_{-\infty}^0 e^{60x} dx

Now we can solve the integral and we got:

5 \frac{e^{60x}}{60} \Big|_{-\infty}^0

\int_{-\infty}^0 5 e^{60x} dx = \frac{e^{60x}}{12}\Big|_{-\infty}^0 = \frac{1}{12} [e^{60*0} -e^{-\infty}]

\int_{-\infty}^0 5 e^{60x} dx = \frac{1}{12}[e^0 -0]= \frac{1}{12}  

So then we see that the integral on this case converges amd the values is 1/12 on this case.

6 0
4 years ago
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Anni [7]

Answer:

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6 0
4 years ago
Read 2 more answers
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