Answer:
square so all sides are equal
bc^2+mc^2=bm^2
16x^2+4x^2=20x^2=2root5x
nd^2+dm^2=nm^2
x^2+4x^2=5x2=root5x
then:-
1/2*b*h=1/2*2root5x*root5x
=1/2*10x^2=5x^2
Let x and y be the dimensions of the rectangle. If the perimeter is 40, we have
We can expression one variable in terms of the others as
Since the area is the product of the dimensions, we have
This is a parabola facing down, so it's vertex is the maximum:
So, the maximum is
And since we know that , we have as well.
This is actually a well known theorem: out of all the rectangles with given perimeter, the one with the greatest area is the square.
I think I went down by 29 dollars and 76 cent
Answer:
<em>x=4</em>
Step-by-step explanation:
Simplifying
4x + 16 + -1x = 22 + 6
Reorder the terms:
16 + 4x + -1x = 22 + 6
Combine like terms: 4x + -1x = 3x
16 + 3x = 22 + 6
Combine like terms: 22 + 6 = 28
16 + 3x = 28
Solving
16 + 3x = 28
Solving for variable 'x'.
Move all terms containing x to the left, all other terms to the right.
Add '-16' to each side of the equation.
16 + -16 + 3x = 28 + -16
Combine like terms: 16 + -16 = 0
0 + 3x = 28 + -16
3x = 28 + -16
Combine like terms: 28 + -16 = 12
3x = 12
Divide each side by '3'.
x = 4
Simplifying
x = 4
Hope this helps! And please correct me if I'm wrong so others can have the correct answer.
Okay, so first off, if you need to graph anything, I suggest Desmos, it's a website with an online graphing calculator. It saved my life for highschool geometry.
Now, to answer your question, your y-intercept is going to be at point (0,2). Your x-intercepts are going to be at points (-2,0) and (-4,0). Your point is at (-3,-1). And then your lines simply extend from there.
Hope this isn't too late to be helpful, good luck with your assignments.