The answer is Yes, you can factor this equation.
He saved 5/24 of his money
Make common denominators
1/6 * 4/4 =4/24
5/8 * 3/3= 15/24
15/24 + 4/24 = 19/24
24/24 - 19/24
= 5/24
the question in English
Draw a rectangle having the base congruent to the nine sevenths of the height.
Let
b-------> the base of rectangle
h-------> the height of rectangle
we know that
b=(9/7)*h-------> this is the equation to obtain the base of the rectangle for a given height
examples
1) for h=7 units
b=(9/7)*7-------->b=9 units
the dimensions are 9 units x 7 units------> see the attached figure
2) for h=5 units
b=(9/7)*5-------->b=(45/7) units
the dimensions are (45/7) units x 5 units
The answer in Italian
Facciamo
b-------> base del rettangolo
h-------> altezza del rettangolo
Noi sappiamo che
b=(9/7)*h-------> questa è l'equazione per ottenere la base del rettangolo per una determinata altezza
esempi
1) per h=7 units
b=(9/7)*7-------->b=9 units
le dimensioni sono 9 units x 7 units----->
vedere la figura allegata
2) per h=5 units
b=(9/7)*5-------->b=(45/7) units
le dimensioni sono (45/7) units x 5 units
Try to relax. Your desperation has surely progressed to the point where
you're unable to think clearly, and to agonize over it any further would only
cause you more pain and frustration.
I've never seen this kind of problem before. But I arrived here in a calm state,
having just finished my dinner and spent a few minutes rubbing my dogs, and
I believe I've been able to crack the case.
Consider this: (2)^a negative power = (1/2)^the same power but positive.
So:
Whatever power (2) must be raised to, in order to reach some number 'N',
the same number 'N' can be reached by raising (1/2) to the same power
but negative.
What I just said in that paragraph was: log₂ of(N) = <em>- </em>log(base 1/2) of (N) .
I think that's the big breakthrough here.
The rest is just turning the crank.
Now let's look at the problem:
log₂(x-1) + log(base 1/2) (x-2) = log₂(x)
Subtract log₂(x) from each side:
log₂(x-1) - log₂(x) + log(base 1/2) (x-2) = 0
Subtract log(base 1/2) (x-2) from each side:
log₂(x-1) - log₂(x) = - log(base 1/2) (x-2) Notice the negative on the right.
The left side is the same as log₂[ (x-1)/x ]
==> The right side is the same as +log₂(x-2)
Now you have: log₂[ (x-1)/x ] = +log₂(x-2)
And that ugly [ log to the base of 1/2 ] is gone.
Take the antilog of each side:
(x-1)/x = x-2
Multiply each side by 'x' : x - 1 = x² - 2x
Subtract (x-1) from each side:
x² - 2x - (x-1) = 0
x² - 3x + 1 = 0
Using the quadratic equation, the solutions to that are
x = 2.618
and
x = 0.382 .
I think you have to say that <em>x=2.618</em> is the solution to the original
log problem, and 0.382 has to be discarded, because there's an
(x-2) in the original problem, and (0.382 - 2) is negative, and
there's no such thing as the log of a negative number.
There,now. Doesn't that feel better.
Complete Question
Two geometrically similar jugs have volumes of 1000 cm³and 512 cm³.They have circular bases. The diameter of the base of the larger jug is 9 cm.
Calculate the diameter of the smaller jug.
Answer:
7.2 cm
Step-by-step explanation:
To solve the above question,we have the proportion
Smaller volume/ Larger volume = (Smaller diameter/ Larger diameter)³
We are to find the smaller diameter
Hence our formula is give as
Cube root(Smaller volume/ Larger volume)= Smaller diameter/ Larger diameter
=cube root( 512/1000) = x/9
= 8/10 = x/9
Cross Multiply
10x = 8 × 9
10x = 72
x = 72/10
x = 7.2cm
Therefore, the diameter of the second jug is 7.2 cm
