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Leviafan [203]
3 years ago
10

Identify the area of the rhombus. PLEASE HELP! I'm desperate!!

Mathematics
1 answer:
Naddika [18.5K]3 years ago
4 0

Area = 1/2(diagonal) * √4*side^2 - diagonal^2

Area = 1/2(16)*√(4*17^2 - 16^2)

Area = 8 * √(4*289-256)

Area = 8 *√900

Area = 8 * 30

Area = 240 m^2

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2/5

Step-by-step explanation:

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3 years ago
PLEASE HELP! PLEASE ANSWER MY QUESTION PLS
andrew-mc [135]

Answer:

Tooth A

Step-by-step explanation:

Since the larger tooth has to be displayed, knowing that no matter how many zeros you add to the end of a decimal, the value of it will stay the same. 0.23 is 1 digit short that 0.195, so if you just add a 0 to 0.23, it make both of them have a digit in the thousandths place. Now it's easier to solve, 0.230>0.195.

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8 0
2 years ago
Inverse laplace of [(1/s^2)-(48/s^5)]
Katen [24]
**Refresh page if you see [ tex ]**

I am not familiar with Laplace transforms, so my explanation probably won't help, but given that for two Laplace transform F(s) and G(s), then \mathcal{L}^{-1}\{aF(s)+bG(s)\} = a\mathcal{L}^{-1}\{F(s)\}+b\mathcal{L}^{-1}\{G(s)\}

Given that \dfrac{1}{s^2} = \dfrac{1!}{s^2} and -\dfrac{48}{s^5} = -2\cdot\dfrac{4!}{s^5}

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From Table of Laplace Transform, you have \mathcal{L}\{t^n\} = \dfrac{n!}{s^{n+1}} and hence \mathcal{L}^{-1}\left\{\dfrac{n!}{s^{n+1}}\right\} = t^n

So you have \mathcal{L}^{-1}\left\{\dfrac{1}{s^2}\right\} - 2\mathcal{L}^{-1}\left\{\dfrac{4!}{s^5}\right\} = \boxed{t-2t^4}.

Hope this helps...
7 0
3 years ago
Explanation on How to answer what is the density of an object that has a mass of 73,430 and the volume of 7 m3
scZoUnD [109]

Answer:

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Step-by-step explanation:

Density = mass ÷ volume

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density = 73,430 ÷ 7

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7 0
2 years ago
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