Used as a way for learners<span> to assess how to apply their patterns, i.e., tether, intensify, or forge their use. Dynamic </span>Learner<span>: refers to the LCI scale scores of an individual who uses one or two patterns at the Use First level and any other combination of Avoid or Use as Needed for the remaining patterns.</span>
So use half the surface area formula: SA=2πr^2 and plug in what you already know
since you don't know the radius yet, solve for it using the circumference
C=2πr
514.96=3.14(2)r
82=r
SA=2π(82)^2
SA=6.28(6724)
SA=42,226.72
so your answer is 42,226.72 yards squared
Answer:
double a;
double b;
double distance = Math.sqrt( (Math.pow(a, 2) + Math.pow(b, 2));
System.out.println("The distance is: " + distance);
Explanation:
The code snippet is written in Java.
First, variable a is declared as a type of double and variable b is also declared as a type of double.
The given formula for the distance is:
√(a² + b²)
So we use the inbuilt function of Java to calculate the power and the square root.
Math.sqrt is to find the square root and it returns a value of type double.
Math.pow is use to calculate the value of a² and b².
a² = Math.pow(a, 2)
b² = Math.pow(b, 2)
Then Math.sqrt is applied to the sum of Math.pow(a, 2) and Math.pow(b, 2), the value is assigned to distance of type double.
The value of distance is now displayed to the user:
System.out.println("The distance is: " + distance);
