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Nataly [62]
3 years ago
15

What is the answer for 5e=3e+36.please show work.

Mathematics
2 answers:
My name is Ann [436]3 years ago
7 0
5e=3e+36\\
2e=36\\
e=18
MissTica3 years ago
3 0
5e=3e+36\ \ \ | subtract\ 3e\\\\
2e=36\ \ \ \ | divide\ by\ 2\\\\
e=18
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There is 5000 ml water in a fish tank. THen 20% water is evaporated per week. calculate the volume of water left after 4 Weeks.
LenaWriter [7]

Answer:

The answer to your question is: V = 2048 ml

Step-by-step explanation:

Data

Volume = 5000 ml

20% is evaporated per week

Volume of water left after 4 weeks = ?

Process

            1st week               5000 ml   -----------------  100 %

                                              x          -----------------      20 %

                                              x = (20x 5000) / 100

                                              x = 1000 ml

After a week there are = 5000 - 1000 = 4000 ml left

            2nd week              4000 ml   ----------------  100 %

                                                x          ----------------   20%

                                               x = 800 ml

After two weeks, there are = 4000 - 800 = 3200 ml left

         third weeks              3200 ml  -----------------  100 %

                                              x         ------------------    20%

                                             x = 640 ml

After three weeks there are 3200 - 640 = 2560 ml left

           

         4rd                             2560 ml  ----------------- 100%

                                                x           ----------------  20%

                                             x = 512 ml

After four weeks there are 2560 - 512 = 2048 ml left

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3 years ago
Marco is 6 feet 3 inches tall. There are 2.54 centimeters in one inch. What is Marcos height in centimeters?
Marat540 [252]

Answer:

190.5cm

Step-by-step explanation:

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3 years ago
Find the quotient of -88 and 11
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3 years ago
Hello, can you please help me I need to write an expression for this word problem
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3 years ago
A large pool of adults earning their first driver’s license includes 50% low-risk drivers, 30% moderate-risk drivers, and 20% hi
Mamont248 [21]

Answer:

The probability that these four will contain at least two more high-risk drivers than low-risk drivers is 0.0488.

Step-by-step explanation:

Denote the different kinds of drivers as follows:

L = low-risk drivers

M = moderate-risk drivers

H = high-risk drivers

The information provided is:

P (L) = 0.50

P (M) = 0.30

P (H) = 0.20

Now, it given that the insurance company writes four new policies for adults earning their first driver’s license.

The combination of 4 new drivers that satisfy the condition that there are at least two more high-risk drivers than low-risk drivers is:

S = {HHHH, HHHL, HHHM, HHMM}

Compute the probability of the combination {HHHH} as follows:

P (HHHH) = [P (H)]⁴

                = [0.20]⁴

                = 0.0016

Compute the probability of the combination {HHHL} as follows:

P (HHHL) = {4\choose 1} × [P (H)]³ × P (L)

               = 4 × (0.20)³ × 0.50

               = 0.016

Compute the probability of the combination {HHHM} as follows:

P (HHHL) = {4\choose 1} × [P (H)]³ × P (M)

               = 4 × (0.20)³ × 0.30

               = 0.0096

Compute the probability of the combination {HHMM} as follows:

P (HHMM) = {4\choose 2} × [P (H)]² × [P (M)]²

                 = 6 × (0.20)² × (0.30)²

                 = 0.0216

Then the probability that these four will contain at least two more high-risk drivers than low-risk drivers is:

P (at least two more H than L) = P (HHHH) + P (HHHL) + P (HHHM)

                                                            + P (HHMM)

                                                  = 0.0016 + 0.016 + 0.0096 + 0.0216

                                                  = 0.0488

Thus, the probability that these four will contain at least two more high-risk drivers than low-risk drivers is 0.0488.

6 0
3 years ago
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