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salantis [7]
3 years ago
10

Which expression forms an equation with the given expression? 8 • 7 - 4 =

Mathematics
1 answer:
zysi [14]3 years ago
8 0
The answer is 52 hopefully this help
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Fourth degree and a single zero of -3
Darya [45]

The degree of a polynomial is the highest power of the polynomial.

The polynomial is \mathbf{P(x) = (x + 3)^4}

The degree is given as:

\mathbf{n = 4}

The zero is given as:

\mathbf{x = -3}

Add 3 to both sides

\mathbf{x  + 3= 0}

From the question, we understand that the polynomial has a single zero.

So, the polynomial is:

\mathbf{P(x) = (x + 3)^n}

Substitute 4 for n

\mathbf{P(x) = (x + 3)^4}

Hence, the polynomial is \mathbf{P(x) = (x + 3)^4}

Read more about polynomials at:

brainly.com/question/11536910

3 0
3 years ago
-13 = 2x +7x -4 help please
Gnoma [55]

Answer:

Just solve for x:

-13 = 9x - 4

9x = -9

x = - 1

4 0
3 years ago
Read 2 more answers
Julie needs to cut 4 pieces of yam, each with the same length, and a piece of yarn 7.75 inches long. Let x represent the
Lapatulllka [165]

Answer:

She has to cut another piece = 7.75 inches

Total length = 4x + 7.75

This is what y represent, so

y = 4x + 7.75

The graph of the equation is continuous

4 0
3 years ago
Iv)<br>6x+3y=6xy<br>2x + 4y= 5xy​
Margaret [11]

Answer:

Ok, we have a system of equations:

6*x + 3*y = 6*x*y

2*x + 4*y = 5*x*y

First, we want to isolate one of the variables,

As we have almost the same expression (x*y) in the right side of both equations, we can see the quotient between the two equations:

(6*x + 3*y)/(2*x + 4*y) = 6/5

now we isolate one off the variables:

6*x + 3*y = (6/5)*(2*x + 4*y) =  (12/5)*x + (24/5)*y

x*(6 - 12/5) = y*(24/5  - 3)

x = y*(24/5 - 3)/(6 - 12/5) = 0.5*y

Now we can replace it in the first equation:

6*x + 3*y = 6*x*y

6*(0.5*y) + 3*y = 6*(0.5*y)*y

3*y + 3*y = 3*y^2

3*y^2 - 6*y = 0

Now we can find the solutions of that quadratic equation as:

y = \frac{6 +- \sqrt{(-6)^2 - 4*3*0} }{2*3} = \frac{6 +- 6}{6}

So we have two solutions

y = 0

y = 2.

Suppose that we select the solution y = 0

Then, using one of the equations we can find the value of x:

2*x + 4*0 = 5*x*0

2*x = 0

x = 0

(0, 0) is a solution

if we select the other solution, y = 2.

2*x + 4*2 = 5*x*2

2*x + 8 = 10*x

8 = (10 - 2)*x = 8x

x = 1.

(1, 2) is other solution

8 0
3 years ago
If m∠RQS=22x-11 and m∠RQT=12x-8, find m∠TQS
Arada [10]

Answer:

∡TQS = 10x -3

Step-by-step explanation:

∡TQS = ∡RQS - ∡RQT

= 22x - 11 - (12x - 8)

= 10x -3

3 0
3 years ago
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