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trasher [3.6K]
3 years ago
15

The length of a rectangular driveway is four feet less than five times the width. The area is 672 feet squared. Find the width a

nd length of the driveway
Mathematics
1 answer:
Svetach [21]3 years ago
7 0

Answer: length of the drive way = 56 feet

Width of the driveway = 12 feet

Step-by-step explanation:

The rectangular driveway has two equal lengths and two equal widths. The area of the driveway is expressed as

length,l × width,w

The area is 672 feet squared. It means that

L×W = 672

The length of the rectangular driveway is four feet less than five times the width. It means that

L = 5W - 4

Substituting L = 5W - 4 into LW = 672

W(5W - 4) = 672

5W^2 - 4W - 672 = 0

5W^2 + 56W - 60W - 672 = 0

W(5W + 56) - 12(5W + 56) = 0

(W - 12)(5W + 56) = 0

W - 12 = 0 or 5W + 56 = 0

W = 12 or 5W = -56

W= 12 or W = - 56/5

The Width cannot be negative , so

W = 12

LW = 672

12L = 672

L = 672/12 = 56

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2 / 1

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4 years ago
You saved $1,240 and your sister agrees to put it in a savings account at her credit union so you can earn interest. You earned
leva [86]

The amount after 2 years is $2,295.

Given that,

  • The invested amount is $1,240.
  • The rate of interest is 8%.
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Based on the above information, the amount after 2 years is

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= $2,295

Therefore we can conclude that the amount after 2 years is $2,295.

Learn more: brainly.com/question/18051939

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3 years ago
Each variable indicates different weights. Which weight can you find? Find it.
SOVA2 [1]

Answer:

We can only be certain that <em>a</em> weighs 12.

There are infinitely many possiblities for <em>b</em> and <em>c</em>.

Step-by-step explanation:

We have the equation:

a+b+c+a+c+b+a+c=12+a+a+b+b+c+c+c

Each variable indicates a weight.

We would like to determine the weights of each variable (if possible).

First, we can rearrange the equation to acquire:

(a+a+a)+(b+b)+(c+c+c)=12+(a+a)+(b+b)+(c+c+c)

We can combine like terms:

3a+2b+3c=12+2a+2b+3c

Notice that both sides have 2<em>b</em> and 3<em>c</em>. Therefore, it is possible for us to cancel them since each nullify the other side. So, we will subtract 2<em>b</em> and 3<em>c</em> from both sides. This yields:

3a=12+2a

Therefore, we can solve for <em>a</em>. Subtract 2<em>a</em> from both sides:

a=12

Hence, the weight of <em>a</em> is 12.

Using the newly acquired information, we can go back to our simplified equation:

3a+2b+3c=12+2a+2b+3c

Since <em>a</em> is 12:

3(12)+2b+3c=12+2(12)+2b+3c

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36+2b+3c=12+24+2b+3c

Simplify:

36+2b+3c=36+2b+3c

We can subtract 36 from both sides:

2b+3c=2b+3c

As you can see, this is a true statement.

Since this is a true statement, there are infinitely many possible values for <em>b</em> and <em>c</em>.

Therefore, the only weight we are <em>certain</em> of knowing is weight <em>a</em> weighing 12.

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The answer should be B
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