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lozanna [386]
3 years ago
6

6. What are the mean and the mode of the following set of data: 5, 12, 1, 5, 7

Mathematics
2 answers:
Firlakuza [10]3 years ago
8 0
Mode is 5 and mean is 6:))
alex41 [277]3 years ago
5 0
The mean =(5+12+1+5+7)/5 =30/5=6
the mode =5
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Solve for x. 23(x−7)=−2 Enter your answer in the box. x = 3
Burka [1]

Answer:

x = 159/23 = 6.913

Step-by-step explanation:

ifyou need help wit this type of stuff go to tigermath.com

4 0
3 years ago
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A line is perpendicular to y=2/3x+2/3 and intersects the point (-2,4). What is the equation of this perpendicular line?
alexira [117]

Answer:

y = - \frac{3}{2} x + 1

Step-by-step explanation:

The equation of a line in slope- intercept form is

y = mx + c ( m is the slope and c the y- intercept )

y = \frac{2}{3} x + \frac{2}{3} ← is in slope- intercept form

with slope m = \frac{2}{3}

Given a line with slope m then the slope of a line perpendicular to it is

m_{perpendicular} = - \frac{1}{m} = - \frac{1}{\frac{2}{3} } = - \frac{3}{2}

Using the point- slope form

with m = - \frac{3}{2} and (x₁, y₁ ) = (- 2, 4) , then

y - 4 = - \frac{3}{2} (x - (- 2) ) , that is

y - 4 = - \frac{3}{2} (x + 2) ← distribute

y - 4 = - \frac{3}{2} x - 3 ( add 4 to both sides )

y = - \frac{3}{2} x + 1 ← in slope- intercept form

5 0
3 years ago
The vet says Ray's puppy will grow to be at most 28 inches tall. Ray's puppy is currently 1 foot tall. How much more will the pu
Nat2105 [25]

28=12+x

28 represents how tall he will get, 12 represents how tall he is in inches, and x is how much he still has left to grow! Hope it helps!

4 0
3 years ago
Someone help me there’s a time limit on it
Westkost [7]

Answer:

P=3

Step-by-step explanation:

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4 0
3 years ago
Roger Waters can scrape up just enough money to rent a canoe for 1 hour and 30 minutes. If he paddles out on a lake at 4 kph and
Inga [223]

Answer:

The distance paddling out on a lake is 2 kilometres and the distance returning back is also 2 kilometres. In total, 4 kilometres.

Step-by-step explanation:

Let t hours be the time it takes Roger to puddle out on a lake. Then \left(1\dfrac{1}{2}-t\right) hours is the time it takes him to return (note that 1 hour and 30 minutes is exactly 1\dfrac{1}{2} hours).

1. If he paddles out on a lake at 4 kph for t minutes, then the distance is

4\cdot t=4t\ km.

2. If he  returns at 2 kph, then the distance is

2\cdot \left(1\dfrac{1}{2}-t\right)=3-2t\ km.

3. These distances are the same, thus

4t=3-2t,\\ \\6t=3,\\ \\t=\dfrac{1}{2}\ hour.

The distance paddling out on a lake is 2 kilometres and the distance returning back is also 2 kilometres. In total, 4 kilometres.

8 0
3 years ago
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