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3 years ago

6. What are the mean and the mode of the following set of data: 5, 12, 1, 5, 7

Mathematics

2 answers:

Firlakuza [10]3 years ago

8 0

Mode is 5 and mean is 6:))

alex41 [277]3 years ago

5 0

The mean =(5+12+1+5+7)/5 =30/5=6
the mode =5

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By coincidence, Kimberly's Paint Supplies sold equal quantities of two paint colors yesterday: yellow and blue. All yellow paint

Vlad1618 [11]

Answer:

36 liters

Step-by-step explanation:

We solve this question using the least common multiple method

Find and list multiples of the liter the blue paint comes in the liters the yellow paint comes in. We find the first common multiple is found. This is the least common multiple.

Multiples of 9:

9, 18, 27, 36, 45, 54

Multiples of 12:

12, 24, 36, 48, 60

Therefore,

LCM(9, 12) = 36

Hence, the smallest amount of each paint color the store must have sold is 36 liters

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3 years ago

1.56 times 48 equals

Crank

Answer:

It equals 74.88

Step-by-step explanation:

U jus multiply them

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3 years ago

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Transitive property of congruence

hodyreva [135]

It states that two objects that are congruent to a third object then they are also congruent to one another.

Step-by-step explanation:

Simple,if one chair is like the second chair and the second chair is like a third chair,then the first chair is like the third chair.

If A=B and

B=C then

A=C

Learn More

Congruence: brainly.com/question/13361468

Keywords : Congruence, transitive property

#learnwithbrainly

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3 years ago

Find the x and y intercept of the line. x-6y=12

Lyrx [107]

The x-intercept is 12 and the y-intercept is -2

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3 years ago

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Find the equation for the plane that contains the line x=−1+3t , y=1+2t, z=2+4t and is perpendicular to the plane containing the

Ivan

Let $L$ be the line given by the vector equation

$(-1,1,2) + \lambda(3,2,4) \ , \lambda \in \mathbb{R}$ .

First, we use the director vectors of the lines L1 and L2 to get the

vector equation of the plane containing them, which we denote by $\Pi_1$ . This is,

$\\\\\Pi_1 : (1,-1,5) + \alpha (2,-1,6) + \beta (1,1,-3) \ , \alpha, \beta \in \mathbb{R}\\\\\\$

We observe that $\vec{N} = (2,-1,6)\times(1,1,-3) = (-3,12,3) \ne (0,0,0)$ . Therefore, the vector equation of $\Pi_1$ defines a plane and $\vec{N}$ is a normal vector to $\Pi_1.$

Finally, the vector equation for the wanted plane, which we denote by $\Pi$ , is

$\Pi : (-1,1,2) + r(3,2,4) + s(-3,12,3), r,s \in \mathbb{R} \ .$

Thus, if $s = 0$ , then $L \subset \Pi$ and since $\vec{N}$ is parallel to $\Pi$ , then it is perpendicular to $\Pi_1$ .

8 0

3 years ago