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3 years ago

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What are the open intervals on which it is increasing?

1 answer:

ivolga24 [154]3 years ago

8 0

Check the picture below.

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in a proportional relationship the ratio y/x is constant. Show that this ratio is not constant for the equation y=a-14

Colt1911 [192]

To show that the ratio $\frac{y}{x}$ is not constant for the function $y=a-14$ we only need to evaluate this function at 2 points and then show that the ratio is not the same for those two points. Note that here $a$ represents $x$ .

To find the counter examples here, I will use the values $a=20$ and $a=28$ . For $a = 20$ , the equation tells us that the output is

$y=20-14=6$ . For this value of $a$ the point is point is $(20,6)$ . The ratio $\frac{y}{x} =\frac{6}{20}$ . For the $a=28$ , $y=28-14=14$ . For this value of $a$ the point is $(28,14)$ . The ratio $\frac{y}{x} =\frac{14}{28} =\frac{1}{2}$ . Clearly this ratio is not constant for all ordered pairs.

8 0

2 years ago

Please any one help me

Ulleksa [173]

$\qquad\qquad\huge\underline{{\sf Answer}}♨$

Since it's a Trapezoid with its non - parallel sides equal to one another,

$\qquad \sf \dashrightarrow \:\angle A + \angle P = 180$

[ By forming co - interior angle pair ]

$\qquad \sf \dashrightarrow \:\angle A +100 = 180$

$\qquad \sf \dashrightarrow \:\angle A = 180 - 100$

$\qquad \sf \dashrightarrow \:\angle A = 80$

Now, similarly,

$\qquad \sf \dashrightarrow \:\angle A + \angle R = 180$

$\qquad \sf \dashrightarrow \: \angle R + 80 = 180$

$\qquad \sf \dashrightarrow \: \angle R = 100$

Similarly,

$\qquad \sf \dashrightarrow \angle K + \angle R = 180$

$\qquad \sf \dashrightarrow \angle K + 100 = 180$

$\qquad \sf \dashrightarrow \angle K = 80$

3 0

2 years ago

Read 2 more answers

if p(x) = x2 – 1 and q(x)=5(x-1), which expression is equivalent to (p – q)(x)? a: 5(x – 1) – x2 – 1 b: (5x – 1) – (x2 – 1) c: (

zavuch27 [327]

P(x) = x^2 - 1
q(x) = 5(x - 1)
(p - q)(x) = (x^2 - 1) - 5(x - 1)

7 0

3 years ago

Read 2 more answers

A worker's earnings e are a function of the number of hours n worked at a rate of 8.75 per hour

andrew11 [14]

E=8.75*n ............................................................................................................................................

3 0

3 years ago

There are 195 adults and 320 children at a zoo. The zoo makes a total of $6,515 from the entrance fees, and the cost of an adult

Ostrovityanka [42]

Answer:

a+c=27

195a+320c=6515

Step-by-step explanation:

adult (a): 195

children (c): 320

total $: $6515

child $: 27

a+c=27 --> c=-a+27

195a+320c=6515

sub the first equation into the 2nd equation to get a=17

sub a=17 into c=-a+27 to get c=10

so, an adult ticket is $17 and a child ticket is $10.

6 0

2 years ago