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3 years ago

What is 0.26 repeating made into a decimal

Mathematics

1 answer:

Savatey [412]3 years ago

3 0

It already is a decimal unless you mean a repeating decimal, it would be .26 with a line over the number.

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aflati masurile a doua unghiuri complementare stiind ca masura unuia dintre ele este cu 18° mai mica decat triplul masurii celui

Ahat [919]

Answer:

The angle is "27 and 63".

Step-by-step explanation:

Let A and B are two angles, in which A is " $\frac{1}{2}$ " complementary angles and B be is another complementary angle.

Condition of complementary angle :

$A+B =90 ......(i)$

Solution:

$\ A = \ 3B - 18 \\\\ \ put \ the \ value \ of \ A \ in \ equation.....(i) \\\\ \ Equation: \\ \\\Rightarrow \ A\ +\ B \ =\ 90 \\\\\Rightarrow \ 3B\ -\ 18 \ + \ B \ = \ 90 \\\\\Rightarrow \ 4B \ = \ 90 +18 \\\\\Rightarrow \ 4B = 108 \\\\ \Rightarrow B = \frac{108}{4} \\\\ \Rightarrow B \ = \ 27\\$

$\ put \ the \ value \ of \ B \ in \ equation (i).\\\\ \ Equation: \\\\\Rightarrow A+B=90\\\\\Rightarrow A+27=90\\\\\Rightarrow A=90-27\\\\\Rightarrow A= 63$

7 0

3 years ago

Step 3a: Calculating the average rate

Alex73 [517]

9514 1404 393

Answer:

a) average rate = (total distance)/(total time)

b) Rave = 2·R1·R2/(R1 +R2)

c) cheetah's average rate ≈ 50.91 mph

Step-by-step explanation:

a) Let AB represent the distance from A to B. Let t1 and t2 represent the travel times (in hours) on leg1 and leg2 of the trip, respectively. Then the distances traveled are...

First leg distance: AB = 70·t1 ⇒ t1 = AB/70

Second leg distance: AB = 40·t2 ⇒ t2 = AB/40

The average rate is the ratio of total distance to total time:

average rate = (AB +AB)/(t1 +t2)

average rate = 2AB/(AB/70 +AB/40) = 2/(1/70 +1/40) = 2(40)(70)/(70+40)

average rate = 560/11 = 50 10/11 . . . mph

No equations are given, so we cannot compare what we wrote with the given equations. In each step of the solution, we have used the rules of algebra and equality.

b) For two rates over the same distance (as above), the average is their harmonic mean:

average rate = 2r1·r2/(r1+r2)

c) The cheetah's average rate was 50 10/11 mph ≈ 50.91 mph.

4 0

2 years ago

Find an equation of the line through the points (-1,1) and (1,5)

bulgar [2K]

First of all, to find the slope, you need to subtract the y's in the numerator over the x's in the denominator. Then you use Y-Y₁=slope(X-X₁) using either of the two points. If you want to simplify it further into slope-intercept form, you need to distribute on the right side of the equation.

5 0

2 years ago

The first blanks options are -2 , -1/2 , 2 , 1/2

Pie

Answer:

equation 1

y = -2x

equation 2

y = x-3

Solution to both

(1,-2)

Step-by-step explanation:

We need to get the equations of both lines

General form is;

y = mx + c

where m is slope and c is the y-intercept

Table 1

since we have a point 0,0; the y-intercept here is zero

Let us get the slope. We can do this by selecting any two points

m = (y2-y1)/(x2-x1)

m = (2-10)/(-1+5) = -8/4 = -2

So the equation of the first line is;

y = -2x

Table 2

we get the slope

m = (4+2)/(7-1) = 6/6 = 1

The partial equation is;

y = x + c

To get c, we select any two point and substitute

4 = 7 + c

c = 4-7

c = -3

So the equation is;

y = x-3

To get the solution to both systems, we equate the y

-2x = x - 3

-2x-x = -3

-3x = -3

x = -3/-3

x = 1

To get y, we substitute;

recall; y = -2x

y = -2(1)

y = -2

Solution to the system is;

(1,-2)

7 0

2 years ago

Solve the absolute value inequality.

Alex Ar [27]

Answer: k ≤ -4 or k ≥ $\frac{4}{3}$

Explanation:

| 3k + 4 | ≥ 8

3k + 4 ≥ 8 or 3k + 4 ≤ -8

-4 -4 -4 -4

3k ≥ 4 or 3k ≤ -12

÷3 ÷3 ÷3 ÷3

k ≥ $\frac{4}{3}$ or k ≤ -4

4 0

2 years ago