All categories

2 years ago

Help, i got the second part but don't understand the first thanks

Mathematics

1 answer:

Masteriza [31]2 years ago

5 0

Answer:

hey how r u please tell me

You might be interested in

What am I supposed to do here?

sweet [91]

Answer:

here is your answer.

Step-by-step explanation:

total frequency is 24

7 0

2 years ago

What type of correlation is suggested by the scatter plot?

Bas_tet [7]

No correlation is suggested

8 0

3 years ago

Match the following differential equations with their solutions. The symbols A, B, C in the solutions stand for arbitrary consta

aleksley [76]

Answer:1

Step-by-step explanation:

4 0

2 years ago

I am drivin 45 miles per hour how far can I drive in 2 hours and 20 minutes

Orlov [11]

45/60= .75 miles each minute
45x2= 90 miles in 2 hours
.75×20=15 miles in 20 min

90+15=105 miles in 2 hours n 20 min

4 0

3 years ago

Read 2 more answers

OC and OR are similar. Find the length of QP.

Elena L [17]

Given:

Circle C and circle R are similar.

The length of arc AB is $s = \frac{22 \pi}{9}$

The radius of circle C (AC) = 4 unit

The radius of circle R (QR) =6 unit

To find the length of arc QP.

Formula

The relation between s, r and $\theta$ is

$arclength = 2\pi r \frac{\theta}{360}$

where,

s be the length of the arc

r be the radius

$\theta$ be the angle.

Now,

For circle C

Taking r = 4

According to the problem,

$2 \pi r \frac{\theta}{360} = \frac{22 \pi}{9}$

or, $2r \frac{\theta}{360} = \frac{22}{9}$ [ eliminating $\theta$ from both side]

or, $\theta = \frac{(22)(360)}{(9)(2)(4)}$

or, $\theta = 110^\circ$

Again,

For circle R

Taking, r = 6 and $\theta = 110^\circ$ we get,

The length of arc QP is

$arc length = 2\pi (6)(\frac{110}{360} )$

or, $arclength = \frac{11 \pi}{3}$

Hence,

The length of QP is $\frac{11 \pi}{3}$ . Option C.

5 0

2 years ago