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3 years ago

20/35 as a fraction in simplest form

Mathematics

2 answers:

zheka24 [161]3 years ago

7 0

$\frac{20}{35}=\frac{4 \times 5}{7 \times 5}=\boxed{\frac{4}{7}}$

tangare [24]3 years ago

7 0

To simplify a fraction, you need only find a number that will fit into both, divide the numerator and denominator by that number, and keep going until you can't find such a number.
For 20/35, we'll use 5.
20 divided by 5 is 4
25 divided by 5 is 7
The reduced fraction is 4/7
And since there isn't any other number that will go into both other than 1, this is the simplest form.
So, the 20/35 in its simplest form is 4/7.

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a rectangle has a length of 15 inches less than 5 times it’s width. If the area of the rectangle is 2750 square inches. what is

irakobra [83]

let L = length and let W = width.

Use the equations 2L + 2W = 2750

and L = 5W + 15

Then do the steps as follows -

1. Plug the equation for what L equals into the first equation

2(5W+15) + 2W = 2750

2. Then distribute the 2

10W + 30 + 2W = 2750

3. Then add like terms

12W + 30 = 2750

4. Then subtract 30 from both sides

12W = 2720

5. Divide by 12 on both sides

W = 226.67

6. Then plug that into the second equation

L = 5(226.67) + 15

L = 1148.35 should be the answer

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2 years ago

I need extra help please, -7y^2-2y^2+y^3y-2y+5y^3-2y

joja [24]

Answer:

How to solve your problem

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-7y^{2}-2y^{2}+y^{3}y-2y+5y^{3}-2y

−7y2−2y2+y3y−2y+5y3−2y

Simplify

Combine exponents

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-7y^{2}-2y^{2}+{\color{#c92786}{y^{3}y}}-2y+5y^{3}-2y

−7y2−2y2+y3y−2y+5y3−2y

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-7y^{2}-2y^{2}+{\color{#c92786}{y^{4}}}-2y+5y^{3}-2y

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Combine like terms

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{\color{#c92786}{-7y^{2}}}{\color{#c92786}{-2y^{2}}}+y^{4}-2y+5y^{3}-2y

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-9y^{2}+y^{4}{\color{#c92786}{-2y}}+5y^{3}{\color{#c92786}{-2y}}

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Rearrange terms

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{\color{#c92786}{-9y^{2}+y^{4}-4y+5y^{3}}}

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{\color{#c92786}{y^{4}+5y^{3}-9y^{2}-4y}}

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2 years ago

Suppose that the probability that any particle emitted by a radioactive material will penetrate a certain shield is 0.01. If 10

AnnyKZ [126]

Answer:

a)P=0.42

b) $n\geq 297$

Step-by-step explanation:

We have a binomial distribution, since the result of each experiment admits only two categories (success and failure) and the value of both possibilities is constant in all experiments. The probability of getting k successes in n trials is given by:

$P=\begin{pmatrix}n\\ k\end{pmatrix} p^k(1-p)^{n-k}=\frac{n!}{k!(n!-k!)}p^k(1-p)^{n-k}$

a) we have k=2, n=10 and p=0.01:

$P=\frac{10!}{2!(10!-2!)}0.01^2(1-0.01)^{10-2}\\P=\frac{10!}{2!*8!}0.01^2(0.99)^{8}\\P=45*0.01^2(0.99)^8=0.42$

b) We have, $1-(1-p)^n=P$ , Here P is the probability that at least one particle will penetrate the shield, this probabity has to be equal or greater than 0.95. Therefore, this will be equal to subtract from the total probability, the probability that the particles do not penetrate raised to the total number of particles.