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kramer
2 years ago
11

Noa was walking in the forest and measured the circumference of two trees that he found. The first tree measured 37 5/8 inches a

round, and the second tree measured 45 1/3 inches around. Noa wanted to find the difference of the circumferences of the two trees. He recorded his steps in the table.
Step 1: 45 1/3- 37 5/8
Step 2: 45 8/24 - 37 15/24
Step 3: 44 32/24 - 37 15/24
Step 4: 44 32/24 - 37 15/24= 8 17/24

In which step did Noa first make an error?
Mathematics
2 answers:
Mademuasel [1]2 years ago
7 0

Answer:

step 4 is correct so D

Step-by-step explanation:

i just took the test

rodikova [14]2 years ago
4 0

Answer:

Step 4: 44 32/24 - 37 15/24= 8 17/24

<u>Here we can finally find out the mistake done by Noa. The result is 7 17/24 and not 8 17/24.</u>

Step-by-step explanation:

1. Let's review carefully all the steps taken by Noa to calculate the difference of the circumferences of the two trees.

Circumference Tree 1 = 37 5/8 inches around

Circumference Tree 2 =  45 1/3 inches around

Step 1: 45 1/3- 37 5/8

The measures are correct, no issues copying them.

Step 2: 45 8/24 - 37 15/24

Noa looked for common denominators

1/3 * 8/8 = 8 /24 is correct; 5/8 * 3/3 = 15/24 is also correct.

Step 3: 44 32/24 - 37 15/24

Noa looked for making the fraction part higher on the left side:

45 8/24 = 44 32/24 is correct because 24/24 = 1

Step 4: 44 32/24 - 37 15/24= 8 17/24

<u>Here we can finally find out the mistake done by Noa. The result is 7 17/24 and not 8 17/24.</u>

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Answer:

a) The calculated value   t =  5.903 > 2.572 at 0.01 level of significance

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Step-by-step explanation:

<u><em>Step(i):-</em></u>

Given mean of the population = 10

Sample size 'n'= 35

Mean of the sample x⁻ = 14.44

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<u><em>Step(ii)</em></u>:-

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Test statistic

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                t = \frac{14.44-10}{\frac{4.45}{\sqrt{35} } }

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tabulated value t₀.₀₁,₃₄  = 2.572

The calculated value   t =  5.903 > 2.572 at 0.01 level of significance

Null hypothesis is rejected at 0.01 level of significance

There is a true mean value is less than 10

<u><em>p- value</em></u> :

p - value  0.00001

The p - value 0.00001  < 0.01

The result is significant at p<0.01

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