Both lines AB and CD are secant lines beacuse in two points they are touching the circunference. There is a Theorem which says the following
Since the distance from the center of the circle to each secant line is the same (5 units), we could assume that the both secant lines are similar. saying:
Then the lenght of CD is:
Referring to the figure, does the triangle shown have
rotational symmetry?
<u>a. yes</u>
b. no
Answer:
Check the explanation
Step-by-step explanation:
Ans=
A: For m = 5: P(³≥1) = 1 – P(³=0) = 1 – 0.9973^5 = 0.0134
M = 10: 1 – 0.9973^10 = 0.0267
M = 20: 1 – 0.9973^20 = 0.0526
M = 30: 1 – 0.9973^30 = 0.0779
M = 50: 1 – 0.9973^50 = 0.126
18)
Ans=
Going by the question and the explanation above, we derived sample values of the mean as well as standard deviation in calculating our probability, since that is the necessary value in determining the probability of an out-of-bounds point being plotted. Furthermore, we would know that that value for the possibility would likely be a poor es²ma²on, cas²ng doubt on anycalcula²ons we made using those values
W = L - 15
WL = 76
(L-15)L = 76
L^2 - 15L - 76 = 0
(L-19)(L+4) = 0
L = 19 or -4
Since a length cannot be negative, the length must be 19 units.
The width is 19-15=4 units.