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AlekseyPX
3 years ago
14

Can someone pls help for brainlest

Mathematics
2 answers:
nalin [4]3 years ago
8 0

Answer:

Step-by-step explanation:

If the diameter of the semicircle is 6, then its radius is 3. The formula we use for this is the area of a circle divided in half, or:

A=\frac{\pi r^2}{2} using 3.14 for pi, as instructed.

A=\frac{(3.14)(3)^2}{2} and

A=\frac{(3.14)(9)}{2} and

A=\frac{28.26}{2} so

A = 14.13 square cm

FromTheMoon [43]3 years ago
7 0

We know that, Area of circle is given by : π × radius²

Semicircle is exactly half of a circle. So, Area of semicircle should be half of the area of a circle.

\implies \sf{Area \ of \ a \ Semicircle = \dfrac{\pi \times (radius)^2}{2}}

Given : Diameter of the semicircle is 6 cm

We know that, Radius is half of the Diameter

So, Radius of the Semicircle : 3 cm

\implies \sf{Area \ of \ the \ given \ Semicircle = \dfrac{\pi \times (3)^2}{2}}

\implies \sf{Area \ of \ the \ given \ Semicircle = \dfrac{3.14 \times 9}{2}}

\implies \sf{Area \ of \ the \ given \ Semicircle = (3.14 \times 4.5)}

\implies \sf{Area \ of \ the \ given \ Semicircle = 14.13 \ square \ centimeters}

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The mean consumption of water per household in a city was 1425 cubic feet per month. Due to a water shortage because of a drough
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Answer:

a)t=\frac{1175-1425}{\frac{250}{\sqrt{100}}}=-10    

The degrees of freedom are given by:

df=n-1=100-1=99  

The p value for this case would be given by:

p_v =P(t_{99}  

Since the p value is significantly lower than he significance level given we have enough evidence to reject the null hypothesis and we can conclude that the true mean is lower than 1425

b) For this case we need to find a critical value in the t distribution with  99 degrees of freedom who accumulates 0.025 of the area in the right tail and we got:

t_{\alpha/2}=1.984

Since the calculated value is higher than the critical value we can reject the null hypothesis at the significance level provided and we can say that the true mean is higher than 1425

Step-by-step explanation:

Information given

\bar X=1175 represent the sample mean for the cubic feets of households

\sigma=250 represent the population standard deviation

n=100 sample size  

\mu_o =1425 represent the value to verify

\alpha=0.025 represent the significance level

t would represent the statistic

p_v represent the p value

Part a

We want to test that the mean consumption of water per household has decreased due to the campaign by the city council, the system of hypothesis would be:  

Null hypothesis:\mu \geq 1425  

Alternative hypothesis:\mu < 1425  

Since we don't know the deviation the statistic is given by:

t=\frac{\bar X-\mu_o}{\frac{s}{\sqrt{n}}}  (1)  

The statistic is given by:

t=\frac{1175-1425}{\frac{250}{\sqrt{100}}}=-10    

The degrees of freedom are given by:

df=n-1=100-1=99  

The p value for this case would be given by:

p_v =P(t_{99}  

Since the p value is significantly lower than he significance level given we have enough evidence to reject the null hypothesis and we can conclude that the true mean is lower than 1425

Part b

For this case we need to find a critical value in the t distribution with  99 degrees of freedom who accumulates 0.025 of the area in the right tail and we got:

t_{\alpha/2}=1.984

Since the calculated value is higher than the critical value we can reject the null hypothesis at the significance level provided and we can say that the true mean is higher than 1425

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The negative of xy≥ 0 is xy<0, x ≥ 0 is x<0 and y ≥ 0 is y<0.

Remember negative means opposite.

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