Answer: 10, 11, & 12
<u>Step-by-step explanation:</u>
Let x represent the age of the youngest child.
Their ages are consecutive so,
Youngest: x
Middle: x + 1
Oldest: x + 2
The age of the Youngest squared (x²) equals 8 times the Oldest [8(x + 2)] plus 4.
x² = 8(x + 2) + 4
x² = 8x + 16 + 4
x² = 8x + 20
x² - 8x - 20 = 0
(x - 10)(x + 2) = 0
x - 10 = 0 or x + 2 = 0
x = 10 or x = -2
Since age cannot be negative, x = -2 is not valid
So, the Youngest (x) is 10
the Middle (x + 1) is 11
and the Oldest (x + 2) is 12
Answrer; apfobofosofoboxldobgk
Explanation; hidofovovvb
Answer:
I believe it would be the last table.
Step-by-step explanation:
A linear function has an equation of y=Mx+b where y and x are the variables but m (the slope) and b are constants. The slope for the last table is -8 as the y values are decreasing by 8 every time you move forward one in the x axis. None of the other tables have a constant slope which means they don’t have straight lines when you graph them. Therefore, the last table would have to be the only one representing a linear function
16 ÷ (4)(2) - 3(2) <span>÷ 2+1
16 </span>÷ 8 - 6 <span>÷ 3
2 - 2
0
Answer: 0</span>
Answer:
WZ = 30
Step-by-step explanation:
set up equation based on WZ = W'Z'
3/4[6x + 10] = 13x - 35
multiply each side of equation by 4 to eliminate fractions:
18x + 30 = 52x - 140
-34x = -170
x = 5
substitute 5 for 'x' in either expression:
13(5) - 35
65 - 35 = 30
