Answer:y=9
Step-by-step explanation:
solution:
Z1 = 5(cos25˚+isin25˚)
Z2 = 2(cos80˚+isin80˚)
Z1.Z2 = 5(cos25˚+isin25˚). 2(cos80˚+isin80˚)
Z1.Z2 = 10{(cos25˚cos80˚ + isin25˚cos80˚+i^2sin25˚sin80˚) }
Z1.Z2 =10{(cos25˚cos80˚- sin25˚sin80˚+ i(cos25˚sin80˚+sin25˚cos80˚))}
(i^2 = -1)
Cos(A+B) = cosAcosB – sinAsinB
Sin(A+B) = sinAcosB + cosAsinB
Z1.Z2 = 10(cos(25˚+80˚) +isin(25˚+80˚)
Z1.Z2 = 10(cos105˚+ isin105˚)
Answer:
x=1
Step-by-step explanation:
Answer:
What the hell AC is not given so you can't find the Perimeter
Step-by-step explanation:
x+10=0
x=-10
AB=x+5
AB=-5
BC=x-2
BC=-12
Area of ABC = 30cm2
<u>Perimeter of ABC = AB+BC+</u><u>AC</u>
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7/8 can be converted to .875 because 1/8 is .125 and .125*7=.875. Add -12 to it so the answer is -12.875