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svet-max [94.6K]
3 years ago
10

A person eats a large pasta meal at lunch and then goes for a run before dinner. Explain how the body taps energy from this star

chy meal.
Biology
2 answers:
Dimas [21]3 years ago
7 0
Starches help give you an extra boost of energy during your workout. <span>Starches, as well as sugars, eventually break down into glucose -- your body's main fuel source.</span>
Ilia_Sergeevich [38]3 years ago
5 0

Starches help give you an extra boost of energy during your workout. Starches, as well as sugars, eventually break down into glucose -- your body's main fuel source.

Explanation:

When you eat starchy foods, you'll have a supported energy level over a period of numerous hours. This is separate from sugars, which are simple polysaccharides that give you a quick surge of energy but do blank to keep your energy levels running.

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Organisms that are similar in structure and form and successfully reproduce among
Goshia [24]
The answer is true.

8 0
3 years ago
Aiden found the density of a rock to be 200 grams/ cubic centimeter. He then found the volume of the rock to be 20 cubic centime
kirill115 [55]
The mass of the rock is 4,000 g because mass= Density multiplied by volume so you do 200 * 20
3 0
3 years ago
Given that the commercial strawberry is an octoploid organism (8n), how many copies of each gene is present in one of the somati
DanielleElmas [232]

Answer:

1. 8 copies of each gene in somatic cells

2. 4 copies of each gene in gametes

Explanation:

According to the question, strawberry is an octoploid organism (8n). This means that it contains 8 sets of chromosomes in its genome. If it contains 8 copies of each chromosome, then it also contains 8 copies of each gene in its body or somatic cell (4 copies from each parent).

However, it will produce gametes or reproductive cells via meiosis. Meiosis is a kind of cell division that reduces the chromosomal number by half. Hence, an octoploid strawberry (8n) with 8 copies of genes will undergo meiosis to produce gametes that have 4 copies of each chromosome and hence, four copies of each gene i.e. 4n (tetraploid).

8 0
4 years ago
You decide to conduct a genetic analysis of these mutant lines by crossing each with a pure-breeding wild-type line. The numbers
maxonik [38]

Complete question:

You will find the complete question in the attached files

Answer:

  • For the twist trait: The <em>mutant allele is dominant</em> to its corresponding wild-type allele
  • For the forked trait: the <em>mutant allele is dominant</em> to its corresponding wild-type allele
  • For the pale trait: The <em>mutant allele is neither dominant nor completely recessive</em> to its corresponding wild-type allele

Explanation:

  • Cross 1:  twisted x wild-type ----> Pure lines

Parentals)    TT   x      tt

<em>F1) twisted leaves, Tt</em>. ---> Heterozygous

Parentals) Tt    x    Tt

Punnett square)    T     t

                       T    TT   Tt

                        t    Tt    tt

<em>F2) 53 twisted, 18 wild-type </em>

Total number of individuals in the F2 = 53 + 18 = 71

71 plants -------- 100% of the F2

53 twisted------X = 75% TT + Tt

18 wild-type----X = 25% tt

<em>Phenotypic ratio 3:1</em>

The phenotype of the F1 and F2 progeny tells us that the twist trait is dominant over the wild type. The fact that the whole F1 generation was twisted is enough information to assume that the wild type is recessive and the twisted is dominant. Also, the phenotypic ratio of the F2 corroborates this assumption.

  • Cross 2: forked x wild-type ---> Pure Lines

Parentals)  FF     x     ff

F1) 100% forked, Ff----> Heterozygous

Parentals)  Ff     x     Ff

Punnett square)    F      f

                    F       FF    Ff

                    f        Ff     ff

F2) 49 forked and 16 wild-type plants

Total number of individuals in the F2 = 49 + 16 = 65

65 plants -------- 100% of the F2

49 forked------X = 75% FF + Ff

16 wild-type----X = 25% ff

<em>Phenotypic ratio 3:1</em>

The phenotype of the F1 and F2 progeny tells us that the twist trait is dominant over the wild type. The fact that the whole F1 generation was forked is enough information to assume that the wild type is recessive and the forked is dominant. Also, the phenotypic ratio of the F2 corroborates this assumption.

  • Cross 3: pale x wild-type ---> Pure lines

Parentals) PP    x    pp

F1) 100% Pp, intermediate color.

Parentals) Pp   x   Pp

Punnett square)   P       p

                      P    PP    Pp

                       p    Pp    pp

F2) 34 intermediate, 17 wild-types, and 16 pale.

Total number of individuals in the F2 = 34 + 17  + 16 = 67

67 plants -------------- 100% of the F2

34 intermediate ------X = 51% Pp

17 wild-type-------------X = 25% pp

16 pale -------------------X = 24% PP

<em>Phenotypic ratio 1:2:1</em>

The phenotype of the F1 and F2 progeny tells us that the pale trait is not dominant neither recessive to the wild type. The fact that the whole F1 generation was intermediate is enough information to assume that none of the traits dominates over the other. This is a case of incomplete dominance.  The heterozygous individual express an intermediate phenotype between both the parentals´ one. Also, the phenotypic ratio of the F2 corroborates this assumption.  

Download pdf
4 0
3 years ago
An organism has the genotype "Aa" for a particular trait. As a result of segregation during meiosis, what alleles will each game
tigry1 [53]

Answer:

one "A" or one "a"

Explanation:

In diploid species (2n), each individual inherits two gene variants (alleles) for each gene, one from the father and one from the mother. This means that each haploid gamete (n) receives one copy of each homologous chromosome that contains only one form of that gene (i.e., one allele). In consequence, and according to Mendel's First Law, alleles segregate into separate gametes (in this case either "A" allele or "a" allele since the parental genotype is heterozygous for this gene).

7 0
3 years ago
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