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viktelen [127]
3 years ago
11

The vectors <4,2> and <-4,-2> are opposite directions and are orthogonal to the vector u = <2,- 4>. That’s bec

ause the dot product of the vectors equals zero. True False
Mathematics
1 answer:
Naddik [55]3 years ago
5 0
This is true since the dot product is zero
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If the period of a sine function is the number of units before the cycle begins to repeat, why would the period of the regressio
Jlenok [28]

Answer:

This means that after going around the unit circle once (2π radians), both functions repeat. So the period of both sine and cosine is 2π . Hence, we can find the whole number line wrapped around the unit circle.

Step-by-step explanation:

5 0
2 years ago
Write a unit test for addinventory(). call redsweater.addinventory() with parameter sweatershipment. print the shown error if th
Katena32 [7]
<span>#include <iostream> using namespace std; class InventoryTag { public: InventoryTag(); int getQuantityRemaining() const; void addInventory(int numItems); private: int quantityRemaining; }; InventoryTag::InventoryTag() { quantityRemaining = 0; } int InventoryTag::getQuantityRemaining() const { return quantityRemaining; } void InventoryTag::addInventory(int numItems) { if (numItems > 10) { quantityRemaining = quantityRemaining + numItems; } } int main() { InventoryTag redSweater; int sweaterShipment = 0; int sweaterInventoryBefore = 0; sweaterInventoryBefore = redSweater.getQuantityRemaining(); sweaterShipment = 25; cout << "Beginning tests." << endl; // FIXME add unit test for addInventory /* Your solution goes here */ cout << "Tests complete." << endl; return 0; }</span>
5 0
3 years ago
Nicole has a collection of dolls that weigh 2/2 gram. How much would 2 dolls weigh?
SashulF [63]

Answer:

2

Step-by-step explanation:

Because 2/2 equals 1, and 1 * 2 = 2

7 0
2 years ago
When 1 is subtracted from three- tenths of the number, the result is equal to one-fifth of a number. What is the number
Bas_tet [7]
Based on the given mathematical statement, it can be rewritten into a mathematical equation to simplify and to be solved easily. The statement, "When one is subtracted from three-tenths of a number" corresponds to the equation, 3x/10 - 1, that is assuming the number is represented by the variable x. This is equal to one-fifth of the number. In other words,
3x/10 - 1 = x/5
x = 10
8 0
2 years ago
Look at the system of equations below.
Annette [7]

Answer:

Substitution and graphing are less efficient methods than elimination for this system as there is extra amount of steps we have to take to solve the same system of equations - hence time consuming and a margin or error may happen. Therefore, elimination is the suitable method for solving this system.

Step-by-step explanation:

Let us consider the system of equation below.

4x-5y=3

3x+5y=13

Elimination method sounds the most appropriate option to solve the given system of equations as we can easily sort out an equation in one variable x in minimal steps by just adding the both equations as the y-coefficient in the first equation is the opposite of the y-coefficient in the second equation, and we can determine an equation in one variable x.

Adding both equations will eliminate the y-variable and we can easily sort out the value of x from the resulting equation.

As the given system of equation

4x-5y=3......[1]

3x+5y=13......[2]

Adding Equation 1 and Equation 2

4x-5y+3x+5y=3+13

7x=16

x=\frac{16}{7}

Putting x=\frac{16}{7} in Equation [1]

4x-5y=3......[1]

y=\frac{43}{35}

Although substitution or graphing methods can also be used to bring the solution of the given system of equations, but using substitution or graphing method can be sometimes cumbersome or time-consuming as it would have to take some additional steps to solve the system.

For example, if we would have to use the substitution methods to solve the given system of equations, first we would have to solve one of the equations by choosing one of the equation for one of the chosen variables and then putting this back into the other equation, and solve for the other, and then back-solving for the first variable.

As the given system of equation

4x-5y=3......[1]

3x+5y=13......[2]

Solving the equation 2 for x variable

3x=13-5y

x=\frac{13-5y}{3}

Plugging x=\frac{13-5y}{3} in equation [1]

4(\frac{13-5y}{3}) -5y=3

y = \frac{43}{35}

Putting y = \frac{43}{35} in Equation 2

3x+5y=13......[2]

x = \frac{16}{7}

So, you can figure out, we have to make additional steps when we use substitution method to solve this system of equations.

Similarly, using graphing method, it would take a certain time before we identify the solution of the system.

Hence, from all the discussion and analysis we did, we can safely say that substitution and graphing are less efficient methods than elimination for this system as there is extra amount of steps we have to take to solve the same system of equations - hence time consuming and a margin or error may happen.

Therefore, we agree with the student argument that Elimination is the best method for solving this system because the y-coefficient in the first equation is the opposite of the y-coefficient in the second equation.

Keywords: substitution method, system of equations, elimination method

Lear more about elimination method of solving the system of equation from brainly.com/question/12938655

#learnwithBrainly

4 0
3 years ago
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