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Varvara68 [4.7K]
4 years ago
11

The perimeter of a square is 60. If one side length of the square is X-4, then what is the value of x

Mathematics
1 answer:
Kamila [148]4 years ago
5 0

Answer:

X= 19

Step-by-step explanation:

If you take 4 away from 19, it equals 15, the perimeter is all sides of the square. Which is 4 sides, 15 x 4 = 60 or 15+15+15+15. The formula for perimeter is all the sides added together.

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If using spss, what is the exact likelihood of obtaining a t-test value at least as extreme or as close to the one that was actu
s2008m [1.1K]

Supposing that the null hypothesis is true, the precise possibility of obtaining a t-test value at least as extreme or as ear to the one that was actually observed was 0.1%. This value can be found in the “Independent Samples t-test” table in the SPSS output, where the exact p value is reported as 0.001. If the null hypothesis is assumed to be true, then statistically noteworthy result should be highly improbable. The rejection of the null hypothesis implies that the correct hypothesis lies in the logical complement of the null hypothesis.

To add, <span>used for non-batched and logical batched statistical analysis, SPSS Statistics was a software package for that specific purpose.</span>

4 0
4 years ago
A baseball diamond is a square whose sides are 9090 feet long. Suppose a player running from second base to third base has a spe
Arada [10]
<h2>Answer:</h2>

<em><u>Rate of change of distance at that instant = 0.066 ft/sec </u></em>

<h2>Step-by-step explanation:</h2>

In the question,

The baseball field is in the square diamond shape.

Side length of square = 9090 ft.

Now,

The player runs from the 2nd base to the 3rd base.

Speed of running of player, v = 30 ft/ sec.

Distance of the player from third base = 20 ft.

Now,

Let us say the distance of the player from the Home base is = l

So,

In the triangle using the Pythagoras theorem, we get,

l^{2}=x^{2}+s^{2}

where, 'x' is the distance of the player from the third base and 's' is the side of the square field base.

So,

l^{2}=x^{2}+s^{2}\\On\,differentiating\,we\,get,\\2l\frac{dl}{dt}=2x\frac{dx}{dt}\\l\frac{dl}{dt}=x\frac{dx}{dt}\\

Now,

Also, at the moment when, x = 20,

Length from the Home base is,

l^{2}=20^{2}+9090^{2}\\l=9090.022\,ft.

Now,

On putting we get,

l\frac{dl}{dt}=x\frac{dx}{dt}\\(9090.022)\frac{dl}{dt}=20(30)\\\frac{dl}{dt}=0.066\,ft./sec.

<em><u>Therefore, the rate of change of distance from the home plate is 0.066 ft/s</u></em>

6 0
4 years ago
Describe electrons.<br> Location: <br> Charge: <br> Mass:
valina [46]

Answer:

Electrons are...

Step-by-step explanation:

Located: In the nucleus

Charged: Positive charge or if you're looking for something more specific the charge of the electron is -1.602 x 10-19 coulmbus (C)

Mass: 9.10938356 × 10^-31 kilograms

6 0
4 years ago
Read 2 more answers
PLEASSE HELP THANK YOU!!!
Inga [223]

Answer:

-3x^4+3x^3+8x^2-2x-5

Step-by-step explanation:

Here we need to move the negative sign to the rest of the variables, and then only add the ones with the same power:

(-2x^4-2x^3+8x^2+2)-(x^4-5x^3+2x+7)\\-2x^4-2x^3+8x^2+2 - x^4+5x^3-2x-7

And then move the variables with the same power closer together

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See how -x^4 and -2x^4 are together?

All we have to do now is combine.

-2x^4-x^4-2x^3+5x^3+8x^2-2x+2-7\\-3x^4+3x^3+8x^2-2x-5

So our answer is -3x^4+3x^3+8x^2-2x-5

3 0
3 years ago
Read 2 more answers
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3 years ago
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