Answer:
The solution of the inequation 
is ![\left(-\infty,-\frac{2}{3}\right]\cup\left[\frac{5}{2},+\infty\right)](https://tex.z-dn.net/?f=%5Cleft%28-%5Cinfty%2C-%5Cfrac%7B2%7D%7B3%7D%5Cright%5D%5Ccup%5Cleft%5B%5Cfrac%7B5%7D%7B2%7D%2C%2B%5Cinfty%5Cright%29)
.
Step-by-step explanation:
First of all, let simplify and factorize the resulting polynomial:
Roots are found by Quadratic Formula:
![r_{1,2} = \frac{\left[-\left(-\frac{11}{6}\right)\pm \sqrt{\left(-\frac{11}{6} \right)^{2}-4\cdot (1)\cdot \left(-\frac{10}{6} \right)} \right]}{2\cdot (1)}](https://tex.z-dn.net/?f=r_%7B1%2C2%7D%20%3D%20%5Cfrac%7B%5Cleft%5B-%5Cleft%28-%5Cfrac%7B11%7D%7B6%7D%5Cright%29%5Cpm%20%5Csqrt%7B%5Cleft%28-%5Cfrac%7B11%7D%7B6%7D%20%5Cright%29%5E%7B2%7D-4%5Ccdot%20%281%29%5Ccdot%20%5Cleft%28-%5Cfrac%7B10%7D%7B6%7D%20%5Cright%29%7D%20%5Cright%5D%7D%7B2%5Ccdot%20%281%29%7D)
and 
Then, the factorized form of the inequation is:
By Real Algebra, there are two condition that fulfill the inequation:
a) 
b) 
The solution of the inequation is .
Corresponding angles for parallel lines r and s cut by transversal q. Corresponding angles are congruent angles.
1 and 9
2 and 10
3 and 11
4 and 12
Corresponding angles for parallel lines p and q cut by transversal s. Corresponding angles are congruent angles.
11 and 15
9 and 13
12 and 16
10 and 14
Corresponding angles for parallel lines p and q cut by transversal r. Corresponding angles are congruent angles.
1 and 5
3 and 7
2 and 6
4 and 8
Linear pair theorem. These 2 angles are equal to 180°
∠1 + ∠2 = 180
∠3 + ∠4 = 180
∠9 + ∠10 = 180
∠11 + ∠12 = 180
∠5 + ∠6 = 180
∠7 + ∠8 = 180
∠13 + ∠14 = 180
∠15 + ∠16 = 180
∠1 + ∠3 = 180
∠2 + ∠4 = 180
∠9 + ∠11 =180
∠10 + ∠12 = 180
∠5 + ∠7 = 180
∠6 + ∠8 = 180
∠13 + ∠15 = 180
∠14 + ∠16 = 180
Vertical angles theorem. Vertical angles are congruent.
1 and 4
2 and 3
9 and 12
10 and 11
5 and 8
6 and 7
13 and 16
14 and 15
the answer should be -4
hope this is correct for you and this helped
Answer:
200
Step-by-step explanation:
Answer:
250
Step-by-step explanation:
