H = 151t - 16t²
The height of the ball when it return to the ground will be 0
0 = 151t - 16t²
The zero product property is that when two numbers are being multiplied and the product is 0, one of them must be equal to 0. Therefore, we can factorize this equation:
16t² - 151t = 0
t(16t - 151t) = 0
By the zero product property:
t = 0 or 16t - 151 = 0
So t = 0 or t = 9.44 seconds
The first solution is before he releases the ball and the second is when the ball comes back to the ground. Thus, the ball's air time is 9.44 seconds.
9514 1404 393
Answer:
Step-by-step explanation:
Let x and y represent amounts invested at 6% and 9%, respectively.
y = 3x +58 . . . . . . . the amount invested at 9%
0.06x +0.09y = 1097.19 . . . . . . total interest earned
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Substituting for y, we have ...
0.06x +0.09(3x +58) = 1097.19
0.33x + 5.22 = 1097.19 . . . . . . . . . simplify
0.33x = 1091.97 . . . . . . . . . . . . subtract 5.22
x = 3309 . . . . . . . . . . . . . . . . divide by 0.33
y = 3(3309) +58 = 9985
$3309 is invested at 6%; $9985 is invested at 9%.
1. x=4, y=0
3. x=2.6666, y=0.3333
Answer:
3. D
4. C
5. I don't know sorry
Step-by-step explanation:
Answer:
Center: (-3,-2)
Radius: √6
The graph is attached.
Step-by-step explanation:
The equation of the circle has the form:
Where (h,k) is the point of the center of the circle and r is the radius of the circle.
The equation given in the problem is
Therefore:
h=-3
k=-2
The center is at (-3,-2)
And the radius is:
Then, you can graph it has you can see in the image attached.
