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4 years ago

Which equation has no solution?

Mathematics

1 answer:

romanna [79]4 years ago

8 0

Answer:

Step-by-step explanation:

4(x+3)+2x=6(x+2)

4x+12+2x=6x+12

6x+12=6x+12

Infinitely Many Solutions

------------------------------------

5+2(3+2x)=x+3(x+1)

5+6+4x=x+3x+3

11+4x=4x+3

11+4x-4x=3

11=3

No Solution

-----------------------------

5(x+3)+x=4(x+3)+3

5x+15+x=4x+12+3

6x+15=4x+15

6x-4x+15=15

2x+15=15

2x=15-15

2x=0

x=0/2

x=0

Answer: x=0

-----------------------------

4+6(2+x)=2(3x+8)

4+12+6x=6x+16

16+6x=6x+16

Infinitely Many Solutions

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At high school basketball game, the athletic department sold 250 tickets and brought in 837.50. Adult tickets cost $5 and studen

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Answer:

The system of equations is:

$a+s = 250\\5a+2.50s = 837.50$

Here a is the number of adult tickets and s is the number of student tickets

Step-by-step explanation:

We will use the given statements to make a system of equations for the given scenario.

First of all we have to decide which variables to be used.

Let a be the number of adult tickets and

Let s be the number of student tickets

So according to the statement that the department sold 250 tickets in total, the equation will be:

$a+s = 250$

This is equation one of the system of equations

According to the statement that cost of adult ticket is $5, total cost of adult tickets will be: $5a$

According to the statement that cost of student ticket is $2.50, total cost of student tickets will be: $2.50s$

The total earning was $837.50 so the second equation will be:

$5a+2.50s = 837.50$

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$a+s = 250\\5a+2.50s = 837.50$

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