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34kurt
3 years ago
6

At high school basketball game, the athletic department sold 250 tickets and brought in 837.50. Adult tickets cost $5 and studen

t tickets cost $2.50. Write a system of equations for this situation.
Mathematics
1 answer:
Tpy6a [65]3 years ago
7 0

Answer:

The system of equations is:

a+s = 250\\5a+2.50s = 837.50

Here a is the number of adult tickets and s is the number of student tickets

Step-by-step explanation:

We will use the given statements to make a system of equations for the given scenario.

First of all we have to decide which variables to be used.

Let a be the number of adult tickets and

Let s be the number of student tickets

So according to the statement that the department sold 250 tickets in total, the equation will be:

a+s = 250

This is equation one of the system of equations

According to the statement that cost of adult ticket is $5, total cost of adult tickets will be: 5a

According to the statement that cost of student ticket is $2.50, total cost of student tickets will be:2.50s

The total earning was $837.50 so the second equation will be:

5a+2.50s = 837.50

Hence,

The system of equations is:

a+s = 250\\5a+2.50s = 837.50

Here a is the number of adult tickets and s is the number of student tickets

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Complete question is;

The levels of mercury in two different bodies of water are rising. In one body of water the initial measure of mercury is 0.05 parts per billion (ppb) and is rising at a rate of 0.1 ppb each year. In the second body of water the initial measure is 0.12 ppb and the rate of increase is 0.06 ppb each year.

Which equation can be used to find y, the year in which both bodies of water have the same amount of mercury?

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D) 0.05y – 0.1 = 0.12y – 0.06

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Option C: 0.05 + 0.1y = 0.12 + 0.06y

Step-by-step explanation:

In the first body, the initial measure of mercury is 0.05 parts per billion (ppb) while it's rising at a rate of 0.1 ppb each year. We are told to use y for the number of years.

Thus, amount of mercury for y years in this first body is;

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Since we want to find the year in which both bodies of water have the same amount of mercury. Thus, it means;

A1 = A2

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0.05 + 0.1y = 0.12 + 0.06y

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