1. From your description, I can infer that the multiplication is:

The first thing we are going to do is simplify the radicands 196 ans 108 (picture 1):

and

Knowing this, we can rewrite our radicals as follows:

Remember that
![\sqrt[n]{x^n} =x](https://tex.z-dn.net/?f=%20%5Csqrt%5Bn%5D%7Bx%5En%7D%20%3Dx)
; in other words if the radicand is raised to the same power as the index of the radical, we can take the radicand out. Since 2 and 7 are raised to the power 2 and the index of the radical is also 2 (square root), we can take out 2 and 7:

Look! we have the same numerator and denominator in our fraction, so we can cancel them both:

Notice that we can write

as

, so we can rewrite our expression one last time:

We can conclude that
the correct option is:
2. The <span>product of a nonzero rational number and an irrational number is always an
irrational number.
Proof by contradiction:
Lets assume that the product of an irrational number and a rational non-zero number is always rational.
Let </span>

be and irrational number and let

and

be two rational numbers with

,

,

, and

are non-zero integers.



Since integers are closed under multiplication,

is a rational number. Since

is an irrational number and

, we have a logical contradiction, so we can conclude that the product of an irrational number and a rational non-zero number is always an
irrational number.