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3 years ago

Order these numbers from least to greatest. 11 , 3.30 , 175 , −10

1 answer:

5 0

If you would like to order the following numbers from least to greatest, you can do this using the following steps:

<span>11, 3.30, 175, - 10
</span>- 10 < 3.30 < 11 < 175

The correct result would be <span>- 10 < 3.30 < 11 < 175</span>.

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A recipe calls for the following ingredients. 3 C flour, 1/2 t salt, 3/4 c sugar, 4 C fruit, 2 t butter.to make 2/3 of the recip

Hatshy [7]

Divide by 3 to each ingredient (gives you a third) and then multiply your answer by two (gives you 2/3). For example, 2 divided by 3 is 2/3, multiply by two and get 1 1/3 t of butter. For the fruits, 4 divided by 3 is 4/3, simplified is 1 1/3, multiply by 2 and get 2 2/3.

8 0

3 years ago

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Let <img src="https://tex.z-dn.net/?f=i" id="TexFormula1" title="i" alt="i" align="absmiddle" class="latex-formula"> be the imag

VLD [36.1K]

$Hey~freckledspots!\\----------------------$

$We~will~solve~for~i^{425}!$

$Rule~of~exponent: a^{b + c} = a^ba^c\\Apply:~i^{425}~=~i^{424}i\\ \\Rule~of~exponent: a^{bc} = (a^{b})^c\\Apply: i^{424} = i(i^2)^{212} \\\\Rule~of~imaginary~number: i^2 = -1\\Apply: i(i^2)^{212} = -1^{212}i\\\\Rule~of~exponent~if~n~is~even: -a^n = a^n\\Apply: -1^{212}i = 1^{212}i\\\\Simplify: 1^{212}i = 1i\\Multiply: 1i * 1 = i\\----------------------\\$

$Now~let's~solve~1^{14}!\\\\Rule~of~exponent: a^{b + c} = a^ba^c\\Apply: i^{14} = (i^2)^7\\\\Rule~of~imaginary~number: i^2 = -1\\Apply: (i^2)^7 = -1^7\\\\Rule~of~exponent~if~n~is~odd: (-a)^n = -a^n\\Apply: -1^7 = -1^7\\\\Simplify: -1^7 = -1\\----------------------\\Now,~we~have: i-1+i^{-14}+i^{44}\\----------------------$

$Now~lets~solve~i^{-14}\\\\Rule~of~exponent: a^{-b} = \frac{1}{a^b} \\Apply: i^{-14} = \frac{1}{i^{14}} \\\\Rule~of~exponent: a^{bc} = (a^b)^c\\Apply: \frac{1}{i^{14}} = \frac{1}{(i^2)^7}\\ \\Rule~of~imagianry~number: i^2 = -1\\Apply: \frac{1}{(i^2)^7} = \frac{1}{-1^7} \\\\Simplify: \frac{1}{-1^7} = \frac{1}{-1} \\\\Rule~of~fractions: \frac{a}{-b} = -\frac{a}{b} \\Apply: \frac{1}{-1} = -\frac{1}{1} = -1\\----------------------\\Now,~we~have: i-1-1+i^44\\----------------------$

$Now~let's~solve~i^{44}!\\\\Rule~of~exponent: a^{bc} = (a^b)^c\\Apply: i^{44} = (i^2)^{22}\\\\Rule~of~imaginary~numbers: i^2 = -1\\Apply: (i^2)^{22} = -1^{22}\\\\Rule~of~exponent~if~n~is~even: (-a)^n = a^n\\Apply: -1^{22} = 1^{22}\\\\Simplify: 1^{22} = 1\\----------------------\\Now,~we~have~i-1-1+1\\----------------------$

$Now~let's~simplify~the~expression!\\\\= i-1-1+1 \\= 1 + i -2\\= -1+i\\----------------------$

$Answer:\\\large\boxed{-1+i}\\----------------------$

$Hope~This~Helped!~Good~Luck!$

8 0

3 years ago

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Please help me I’m crying right now

Semenov [28]

Answer:

24ft²

Step-by-step explanation:

Dude. Go back and relearn the concept man. This is the third time you've been asking the same subject.

Area of triangle = ½BH = ½(6)(8) = 24

5 0

3 years ago

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A tank that holds up 10 gallons. when its active, a drain empties water from the tank at a constant rate, when Jada first see th

Mamont248 [21]

Answer:

-2/3 gallon/minute

Step-by-step explanation:

In three minutes the water volume has decreased by 2 gallons (7 less 5 is 2). The unit rate of decrease of the amount of water in the tank is thus:

- 2 gallons

------------------- = -2/3 gallon/minute

3 minutes

6 0

3 years ago

What is the Domain and Range *DON'T FORGET PARENTHESES AND BRACKETS*

Anastasy [175]

Answer:

Domain: (-5,-4,-3,-2,-1,0,1,2,3,4,5)

Range: (0,1,2,3,4, -1, -2)

Step-by-step explanation:

Domain means all of the x-axis values on the graph, so for example in (-2,0), -2 would be part of the domain and 0 part of the range. Therefor, what you would do would be take all of the plots and put all x values as the domain and all y values as the range. Hope this helped!

4 0

3 years ago