Ask question

Ask question

All categories

3 years ago

10

I need help with one more question in my homework

1 answer:

tankabanditka [31]3 years ago

5 0

The vertex is (0, 6) and the axis of symmetry is x = 0, or the y-axis.

To find the vertex, you can quickly change it to vertex form.

y= 2(x - 0)^2 + 6, the vertex can be seen as (0, 6).

The axis of symmetry is always the x value through the x-coordinate of the vertex.

You might be interested in

add and simplify 9/16=1/2=?

dolphi86 [110]

$\frac{9}{16}+\frac{1}{2}=\frac{9}{16}+\frac{8}{16}=\frac{17}{16}=1\frac{1}{16}$

I hope I helped :D

4 0

3 years ago

Read 2 more answers

A landscape contractor planted 37 tulip bulbs, 53 daffodil bulbs, and 82 crocus bulbs in each field. He planted bulbs in 174 fie

SCORPION-xisa [38]

The total number of bulbs the landscape contractor planted is 29,928 so the answer is D.

5 0

4 years ago

I need to find the value of X !

vovangra [49]

The angle right above 4x is equal to x

and 4x + x = 180

5x = 180

/5 /5

x = 36

5 0

3 years ago

Write the equation of the line that is parallel to the given segment and that passes through the point (-3,0).

grandymaker [24]

Answer:

Option (B)

Step-by-step explanation:

In the figure attached,

A straight line is passing through two points (0, 2) and (3, 1).

Slope of this line ( $m_1$ ) = $\frac{y_2-y_1}{x_2-x_1}$

= $\frac{2-1}{0-3}$

= $-\frac{1}{3}$

Let the slope of a parallel to the line given in the graph = $m_2$

By the property of parallel lines,

$m_1=m_2$

$m_2=-\frac{1}{3}$

Equation of a line passing through a point (x', y') and slope 'm' is,

y - y' = m(x - x')

Therefore, equation of the parallel line which passes through (-3, 0) and having slope = $-\frac{1}{3}$ will be,

$y-0=-\frac{1}{3}(x+3)$

$y=-\frac{1}{3}x-1$

Option (B). will be the answer.

5 0

3 years ago

A construction crew is building a two story house, but they have not built the staircase between the floor yet. The height of th

Naya [18.7K]

Answer:

13.4feet

Step-by-step explanation:

The set up forms a right triangle.

Given

Height of the staircase h = 12 feet

Base of the stairs b = 6feet

Required

Length of the ramp l

Using the pythagoras theorem

l² = h² + b²

l² = 12²+6²

l² = 144 + 36

l² = 180

l = √180

l = 13.42 feet

Hence the length of the ramp to the nearest tenth is 13.4feet

6 0

3 years ago