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3 years ago

What is the length of the missing side? Round to the nearest tenths if necessary.

Mathematics

1 answer:

DENIUS [597]3 years ago

4 0

Answer:

$\sqrt{207}$

Step-by-step explanation:

Use the right triangle formula c^2=a^2+b^2

C is the number of the hypothenuse while b and c are the 2 others.

16^2=7^2+a^2

256=49+a^2

now solve for the equation.

a^2=207

now take the square root of both.

a= $\sqrt[2]{207}$

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What is the value of 36x-8y2 when x=3 and y=-6

dem82 [27]

36x−8y2 x=3 and y=−6(36)(3)−8(−6)2=−180

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3 years ago

Evaluate the expression. 9! − 5!

Minchanka [31]

! means factorial, if you did not already know. It means multiply together all the numbers leading up to that number. For example, 4! = 4x3x2x1 = 24
Evaluate means just solve it.
9! = 9x8x7x6x5x4x3x2x1 = 362880
5! = 5x4x3x2x1 = 120
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There is your answer

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4 years ago

Read 2 more answers

I need help on this question

Helga [31]

Answer:

slope =( y2 - y1 ) ÷ (x2 - x1)

Step-by-step explanation:

p1 ( -1 , -2)

p2 (4 , 2 )

slope =

$\frac{2 - ( - 2)}{4 - ( - 1)} = \frac{4}{5}$

8 0

3 years ago

A trains leaves Cincinnati at 2:00 pm.A second train leaves the same station in the same direction at 4:00 pm.The second train t

kvasek [131]

Answer:

Speed of first train = 36 mph

Speed of second train = 60 mph

Step-by-step explanation:

Given:

First train leaves Cincinnati at 2:00 PM

Second train leaves same station at 4:00 PM

Speed of second train is 24 mph faster than first train.

The second train overtakes the first at 7:00 PM

To find the speeds of each train.

Solution:

First train:

Let speed of first train be = $x\ mph$

Time of travel between 2:00 PM to 7:00 PM = $7-2=5\ h$

Distance traveled by 1st train in 5 hours in miles = $Speed\times time = x\times 5 = 5x$

Second train:

Then, speed of second train will be = $(x+24)\ mph$

Time of travel between 4:00 PM to 7:00 PM = $7-4 = 3\ h$

Distance traveled by second train in 3 hours in miles = $Speed\times time = (x+24)\times 3=3x+72$

At 7:00 PM both trains meet as the second train overtakes the first. This means the distance traveled by both the trains is same at 7:00 PM as they both leave from same stations.

Thus, we have:

$5x=3x+72$