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topjm [15]
3 years ago
13

Pls help with some halfof problems​

Mathematics
2 answers:
charle [14.2K]3 years ago
8 0

Answer:

Step-by-step explanation:

its b

vivado [14]3 years ago
7 0
Answer


They are both B
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Find the value of YZ
ASHA 777 [7]

Answer:

YZ = 44

Step-by-step explanation:

Let the intersection of XW and YZ equal A. For this problem, we can use power of a point in the scenario where two secants intersect in the interior of a circle. We get the equation:

WA * AX = ZA * AY

We can substitute the values we are given to get:

(2x - 6)(21) = (x + 1)(30)

42x - 126 = 30x + 30

12x - 126 = 30

12x = 156

x = 13

Using segment addition postulate, we can say that:

YZ = YA + AZ

And we can plug in what we know from the diagram:

YZ = 30 + x + 1

We can also plug in the value of x, 13

YZ = 30 + 13 + 1 = 44

5 0
3 years ago
Solve the absolute value inequality.<br> |1x + 7|&gt; 3
snow_tiger [21]

Answer: x>−4 or x<−10

Step-by-step explanation:

brainliest plzz:)

4 0
3 years ago
What is -5xy and 8yx combined
BlackZzzverrR [31]

Answer:

3xy

Step-by-step explanation:

4 0
3 years ago
Read 2 more answers
Consider the probability that at most 85 out of 136 DVDs will work correctly. Assume the probability that a given DVD will work
Hoochie [10]

Answer:

Since both np \geq 10 and n(1-p) \geq 10, the necessary conditions are satisfied.

0.9945 = 99.45% probability that at most 85 out of 136 DVDs will work correctly.

Step-by-step explanation:

Test if the normal curve can be used as an approximation to the binomial probability by verifying the necessary conditions.

It is needed that:

np \geq 10 and n(1-p) \geq 10

Binomial probability distribution

Probability of exactly x successes on n repeated trials, with p probability.

Can be approximated to a normal distribution, using the expected value and the standard deviation.

The expected value of the binomial distribution is:

E(X) = np

The standard deviation of the binomial distribution is:

\sqrt{V(X)} = \sqrt{np(1-p)}

Normal probability distribution

Problems of normally distributed distributions can be solved using the z-score formula.

In a set with mean \mu and standard deviation \sigma, the z-score of a measure X is given by:

Z = \frac{X - \mu}{\sigma}

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the p-value, we get the probability that the value of the measure is greater than X.

When we are approximating a binomial distribution to a normal one, we have that \mu = E(X), \sigma = \sqrt{V(X)}.

Assume the probability that a given DVD will work correctly is 52%.

This means that p = 0.52

136 DVDs

This means that n = 136

Test the conditions:

np = 136*0.52 = 70.72 \geq 10

n(1-p) = 136*0.48 = 65.28 \geq 10

Since both np \geq 10 and n(1-p) \geq 10, the necessary conditions are satisfied.

Mean and standard deviation:

\mu = E(X) = np = 136*0.52 = 70.72

\sigma = \sqrt{V(X)} = \sqrt{np(1-p)} = \sqrt{136*0.52*0.48} = 5.83

Consider the probability that at most 85 out of 136 DVDs will work correctly.

Using continuity correction, this is P(X \leq 85 + 0.5) = P(X \leq 85.5), which is the p-value of Z when X = 85.5. So

Z = \frac{X - \mu}{\sigma}

Z = \frac{85.5 - 70.72}{5.83}

Z = 2.54

Z = 2.54 has a p-value of 0.9945.

0.9945 = 99.45% probability that at most 85 out of 136 DVDs will work correctly.

4 0
3 years ago
For the following sequence determine the common difference (if it is an arithmetic sequence) or the common ratio (if it is a geo
qwelly [4]

Answer:

The first one is the answer.

Step-by-step explanation:

It's an arithmetic sequence. It has a common difference.

d = an - a_n-1

an = -12x + 12

a_n-1 = - 7x + 8

d = -12x + 12 - (-7x + 8)

d = -12x + 12 + 7x - 8

d = -5x + 4

Try  it. Let's try for the third term

-12x + 12 - 5x + 4

- 17x + 15 which is exactly what the third term is.

5 0
3 years ago
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