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Sladkaya [172]
3 years ago
5

an athlete completes a race in 55.72 seconds how many times greater is the digit in the tens place than the digit in the ones pl

ace
Mathematics
2 answers:
Inessa05 [86]3 years ago
7 0
7 is 5 greater than the 2
kvasek [131]3 years ago
5 0

Answer:

The value of digit in tens place is 10 times greater than the value of digit in ones place.

Step-by-step explanation:

Let the value of digit in tens place be x times the value of digit in ones place.

We are asked to find the value of the digit in the tenths place is how many times as much as the value of the digit in the thousandths place.

55.72

Ones: 5

Tens: 5

\text{5-ones}=5

\text{5-tens}=5\times 10=50

x\cdot\text{Ones-digit}=\text{Tens-digit}

x\cdot5=50

\frac{x\cdot5}{5}=\frac{50}{5}

x=10

Therefore, the value of the digit in the tens place is 10 times greater than the value of the digit in the ones place.

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From the sum of - 17 and 16, subtract the sum of - 9 and 22.​
harkovskaia [24]

Answer:

-14

Step-by-step explanation:

-17 + 16 = -1

-9 + 22 = 13

-1 - 13 = -14

3 0
3 years ago
A vendor bought 80 pineapples ₱18.50 each. Three pineapples got rotten, but then he sold the rest at ₱25.00 each. how much did h
Hatshy [7]

Answer:

₱445

Step-by-step explanation:

₱18.50(x)

x = number of pineapples purchased

₱18.50(80) = ₱1480

80 - 3 = 77

₱25.00(z)

z = number of pineapples resold.

25.00(77) = ₱1925

₱1925 = ₱1480 = ₱445

5 0
3 years ago
Answer this question plz
weqwewe [10]
The correct answer is b Bc he sent 25$
8 0
3 years ago
Read 2 more answers
I need help in this!
In-s [12.5K]

For a function to begin to qualify as differentiable, it would need to be continuous, and to that end you would require that a is such that

\displaystyle\lim_{x\to0^-}g(x)=\lim_{x\to0^+}g(x)\iff\lim_{x\to0}ax=\lim_{x\to0}x^2-3x

Obviously, both limits are 0, so g is indeed continuous at x=0.

Now, for g to be differentiable everywhere, its derivative g' must be continuous over its domain. So take the derivative, noting that we can't really say anything about the endpoints of the given intervals:

g'(x)=\begin{cases}a&\text{for }x0\end{cases}

and at this time, we don't know what's going on at x=0, so we omit that case. We want g' to be continuous, so we require that

\displaystyle\lim_{x\to0^-}g'(x)=\lim_{x\to0^+}g'(x)\iff\lim_{x\to0}a=\lim_{x\to0}2x-3

from which it follows that a=-3.

3 0
3 years ago
Help me :( please help me
Katena32 [7]

Answer:

22.84, 5.83

Step-by-step explanation:

Pythagoras theorem states that: a^2+b^2=c^2

So, for red triangle, it will be: 9^2+21^2=b^2

81+441=b^2

522=b^2

square root of 522=b

22.84=b

For purple one,

3^2+5^2=a^2

9+25=a^2

34=a^2

square root of 34=a

5.83=a

7 0
2 years ago
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