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2 years ago

Solve for k. 8k + 2m = 3m + k

Mathematics

2 answers:

Bingel [31]2 years ago

5 0

Solve for k by simplifying both sides of the equation, then isolating the variable.

k = m/7

Zielflug [23.3K]2 years ago

5 0

Let's use algebra and solve for k.

$8k+2m=3m+k\\8k-k=3m-2m$ (putting k on one side and m on another)

$7k=m\\k=\frac{m}{7}$

This is the final answer.

ANSWER: $k=\frac{m}{7}$

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Determine which expression has the greatest value.

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n airplane took off from an airport and traveled at a constant rate and angle of elevation. When the airplane reached an altitud

hram777 [196]

The angle of the plane when it rose from the ground is 64.8 degrees

<h3>Application of trigonometry identity</h3>

Given the following parameters from the question

Altitude of the airplane H = 500m

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According to the trigonometry identity

tan x = opposite/adjacent

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Learn more on angle of elevation here: brainly.com/question/88158

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2 years ago

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3 years ago

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Consider the following hypothesis test:

Gnom [1K]

Answer:

a. z=3.09. Yes, it can be concluded that the population mean is greater than 50.

b. z=1.24. No, it can not be concluded that the population mean is greater than 50.

c. z=2.22. Yes, it can be concluded that the population mean is greater than 50.

Step-by-step explanation:

We have a hypothesis test for the mean, with the hypothesis:

$H_0: \mu\leq50\\\\H_a:\mu> 50$

The sample size is n=55 and the population standard deviation is 6.

The significance level is 0.05.

We can calculate the standard error as:

$\sigma_M=\dfrac{\sigma}{\sqrt{n}}=\dfrac{6}{\sqrt{55}}=0.809$

For a significance level of 0.05, the critical value for z is zc=1.644. If the test statistic is bigger than 1.644, the null hypothesis is rejected.

a. If the sample mean is M=52.5, the test statistic is:

$z=\dfrac{M-\mu}{\sigma_M}=\dfrac{52.5-50}{0.809}=\dfrac{2.5}{0.809}=3.09$

The null hypothesis is rejected, as z>zc and falls in the rejection region.

b. If the sample mean is M=51, the test statistic is:

$z=\dfrac{M-\mu}{\sigma_M}=\dfrac{51-50}{0.809}=\dfrac{1}{0.809}=1.24$

The null hypothesis failed to be rejected, as z<zc and falls in the acceptance region.

c. If the sample mean is M=51.8, the test statistic is:

$z=\dfrac{M-\mu}{\sigma_M}=\dfrac{51.8-50}{0.809}=\dfrac{1.8}{0.809}=2.22$

The null hypothesis is rejected, as z>zc and falls in the rejection region.

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3 years ago