Answer:
Step-by-step explanation:
Charge on atom is due to electron
Electron have negative charge while proton have positive charge and neutron have no charge. If there are 10 proton (10 positive charge)
Answer:
1. -1
2. 5
3. 14
4. 26
Step-by-step explanation:
Answer:
no guaranteed classification
Step-by-step explanation:
We know that the quadrilateral has two pairs of congruent sides. Both a rectangle and a parallelogram have two pairs of congruent sides. The difference between them is their angles. But we don't know anything about the angles in the figure, so we cannot know which kind it is.
The confidence interval for a <span>(1−α)%</span> confidence level is given by
<span>
(<span>θ0</span>−<span>Z<span>α/2 </span></span><span>σ/√n</span>, <span>θ0</span>+<span>Z<span>α/2 </span></span><span>σ/√n</span>)
</span><span>θ0</span> is the measured statistic, <span>Z<span>α/2</span></span> is the cutoff/critical value, and <span>σ/<span>√n</span></span> is the standard error. σ is the population standard deviation (if known) or can be estimated by a sample standard deviation. n is the sample size.
The cutoff value depends on the test you wish to use, and <span>θ0</span><span> depends on the statistic you wish to estimate.</span>
Answer:
- The shaded region is 9.83 cm²
Step-by-step explanation:
<em>Refer to attached diagram with added details.</em>
<h2>Given </h2>
Circle O with:
- OA = OB = OD - radius
- OC = OD = 2 cm
<h2>To find</h2>
<h2>Solution</h2>
Since r = OC + CD, the radius is 4 cm.
Consider right triangles OAC or OBC:
- They have one leg of 2 cm and hypotenuse of 4 cm, so the hypotenuse is twice the short leg.
Recall the property of 30°x60°x90° triangle:
- a : b : c = 1 : √3 : 2, where a- short leg, b- long leg, c- hypotenuse.
It means OC: OA = 1 : 2, so angles AOC and BOC are both 60° as adjacent to short legs.
In order to find the shaded area we need to find the area of sector OADB and subtract the area of triangle OAB.
Area of <u>sector:</u>
- A = π(θ/360)r², where θ- central angle,
- A = π*((mAOC + mBOC)/360)*r²,
- A = π*((60 + 60)/360))(4²) = 16.76 cm².
Area of<u> triangle AO</u>B:
- A = (1/2)*OC*(AC + BC), AC = BC = OC√3 according to the property of 30x60x90 triangle.
- A = (1/2)(2*2√3)*2 = 4√3 = 6.93 cm²
The shaded area is:
- A = 16.76 - 6.93 = 9.83 cm²