Tanikwa started a new exercise program using the indoor track. In her first workout she ran 8 laps for every 4 laps that she wal
1 answer:
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Answer:
16.9 units
Step-by-step explanation:
Sometimes the easiest way to work these problems is to get a little help from technology. The GeoGebra program/app can tell you the length of a "polyline", but it takes an extra segment to complete the perimeter. It shows the perimeter to be ...
14.87 + 2 = 16.87 ≈ 16.9 . . . units
_____
The distance formula can be used to find the lengths of individual segments. It tells you ...
d = √((Δx)² +(Δy)²)
where Δx and Δy are the differences between x- and y-coordinates of the segment end points.
If the segments are labeled A, B, C, D, E in order, the distances are ...
AB = √(5²+1²) = √26 ≈ 5.099
BC = √(1²+3²) = √10 ≈ 3.162
CD = Δx = 3
DE = √(3²+2²) = √13 ≈ 3.606
EA = Δy = 2
Then the perimeter is ...
P = AB +BC +CD +DE +EA = 5.099 +3.162 +3 +3.606 +2 = 16.867
P ≈ 16.9
Answer:
a) 0.152 = 15.2% probability that this person is a female who engages in physical exercise activities during the lunch hour.
b) 0.248 = 24.8% probability that this person is a female who does not engage in physical exercise activities during the lunch hour.
Step-by-step explanation:
Question a:
20% of employees engage in physical exercise.
This 20% is composed by:
8% of 60%(males)
x% of 100 - 60 = 40%(females).
Then, x is given by:
0.38 = 38%
Probability of being a female who engages in exercise:
40% are female, 38% of 40% engage in exercise. So
0.38*0.4 = 0.152
0.152 = 15.2% probability that this person is a female who engages in physical exercise activities during the lunch hour.
B. If we choose an employee at random from this corporation,what is the probability that this person is a female who does not engage in physical exercise activities during the lunch hour?
40% are female, 100% - 38% = 62% of 40% do not engage in exercise. So
0.62*0.4 = 0.248
0.248 = 24.8% probability that this person is a female who does not engage in physical exercise activities during the lunch hour.