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2 years ago

What are the roots of the quadratic equation X² + 4X + 4. How many roots are there.

1 answer:

3 0

If we set the equation equal to 0, we can factor it to find its roots:

x² + 4x + 4 = 0
(x + 2)(x + 2) = 0
x = -2

This graph has one root, a double root, at -2. This means that a single point, which must be the vertex of the parabola, touches the x-axis at (-2, 0)

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Solve the system of equations. y=23x–19 x2–y= – 6x–23 Write the coordinates as integers, simplified proper or improper fractions

forsale [732]

Answer:

(3, 50) and (14,303)

Step-by-step explanation:

Given the system of equations;

y=23x–19 ....1

x²–y= – 6x–23 ...2

Substitute 1 into 2;

x²–(23x-19)= – 6x–23

x²–23x+19= – 6x–23 .

x²-23x + 6x + 19 + 23 = 0

x² - 17x + 42 = 0

Factorize;

x² - 14x - 3x + 42 = 0

x(x-14)-3(x-14) = 0

(x-3)(x-14) = 0

x = 3 and 14

If x = 3

y = 23(3) - 19

y = 69-19

y = 50

If x = 14

y = 23(14) - 19

y = 322-19

y = 303

Hence the coordinate solutions are (3, 50) and (14,303)

8 0

2 years ago

PLEASE HELP ASAP IM GIVING BRAINLIST TO THE BEST ANSWER!

ehidna [41]

Answer:

E. y - 4 = 6(x+2) is the answer

slope:

m = -8-4/-4+2 = 6

Formula:

y - ys1 = m(x - xs1)

hope this helps!

Step-by-step explanation:

4 0

2 years ago

What is 28.6 - 0.975 and I need an explanation.

bekas [8.4K]

The answer is 27.625 !

hope this helpss !!

8 0

2 years ago

Read 2 more answers

George would like to build a garden this year, George measure out his proposed garden and would like to know how many square fee

Blababa [14]

Answer:

The area is 105.5ft^2

Step-by-step explanation:

Required

The area of the composite figure

The figure can be divided to 2 shapes

(1) Rectangle: Length = 6ft and Width = 8ft

(2) Trapezoid: Height = 5ft (i.e. 8 - 3), Parallel sides = 9ft and 14ft (i.e. 20 - 6)

The area of the rectangle is:

$Area = 6 * 8 = 48$

The area of the trapezoid is:

$Area = \frac{1}{2}(9 + 14) * 5$

$Area = \frac{1}{2}(23) * 5$

$Area = 11.5 * 5$

$Area = 57.5$

So, the area of the garden is:

$Total = 48 + 57.5$

$Total = 105.5$

5 0

2 years ago

Suppose that a cyclist began a 476

mojhsa [17]

Well, we know the cyclist left the western part going eastwards, at the same time the car left the eastern part going westwards

the distance between them is 476 miles, and they met 8.5hrs later

let's say after 8.5hrs, the cyclist has travelled "d" miles, whilst the car has travelled the slack, or 476-d, in the same 8.5hrs

we know the rate of the car is faster... so if the cyclist rate is say "r", then the car's rate is r+33.2

thus $\bf \begin{array}{lccclll}
&distance&rate&time\\
&-----&-----&-----\\
\textit{eastbound cyclist}&d&r&8.5\\
\textit{westbound car}&476-d&r+33.2&8.5
\end{array}\\\\
-----------------------------\\\\
\begin{cases}
\boxed{d}=8.5r\\\\
476-d=(r+33.2)8.5\\
----------\\
476-\boxed{8.5r}=(r+33.2)8.5
\end{cases}$

solve for "r", to see how fast the cyclist was going

what about the car? well, the car's rate is r + 33.2

6 0

2 years ago