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Bad White [126]
2 years ago
13

The radius of the base of a cylinder is 27 cm and its height is 37 cm. Find the surface area of the cylinder in terms of π

Mathematics
2 answers:
Nonamiya [84]2 years ago
7 0
Surface area of a cylinder = 2 x Pi x r^2 + 2 x Pi x r x h

R = 27 cm
H = 37 cm

Take away the Pi seeing as you want to keep it in terms of Pi

2 x 27^2 + 2 x 27 x 37 = 3456 Pi cm^2
Your answer is B
Dvinal [7]2 years ago
3 0

Answer: the surface area of the cylinder in terms of π is 3,456 π cm² (option B ).

Step-by-step explanation:

Hi, to answer this question we have to analyze the information given:

Radius of the base of cylinder r = 27cm  

Height of the cylinder h = 33cm  

Surface area of the Cylinder = Area of two base circles + Area of rolled  

Area of each circle base is π x r². So, the area of two base circles is 2π x r².

Area of the area rolled: 2 x π x r x h  

Replacing the variables with the values given:

Surface area = 2π x r² + 2 x π x r x h  

s = 2 x π x 27² + 2 x π x 27x 37

s = 1,458 π + 1,998 π

s= 3,456 π

In conclusion, the surface area of the cylinder in terms of π is 3,456 π cm²(option B ).

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Which relationships describe angles 1 and 2? Select each correct answer. vertical angles adjacent angles O complementary angles
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5 0
2 years ago
What is the perimeter of a rectangular garden with a width of 24 feet and a diagonal of 40 feet?
elena55 [62]
Drawing it out, as seen, using the Pythagorean theorem we get that w^2+l^2 (with w=width and l=length)=diagonal^2=24^2+l^2=40^2. Subtracting 24^2 from both sides, we get 40^2-24^2=l^2=1024. Square rooting both sides, we get l=32. Since the perimeter is 2w+2l, we get 32*2+24*2=64+48=112

8 0
3 years ago
Two cars simultaneously left Points A and B and headed towards each other, and met after 2 hours and 45 minutes. The distance be
zheka24 [161]
<h2>Hello!</h2>

The answer is:

FirstCarSpeed=41mph\\SecondCarSpeed=55mph

<h2>Why?</h2>

To calculate the speed of the cars, we need to write two equations in order to create a relation between the two speeds and be able to isolate one in function of the other.

So, let be the first car speed "x" and the second car speed "y", writing the equations we have:

For the first car:

x_{FirstCar}=x_o+v*t

For the second car:

We know that the speed of the second car is the speed of the first car plus 14 mph, so:

x_{SecondCar}=x_o+(v+14mph)*t

Now, we already know that both cars met after 2 hours and 45 minutes, meaning that positions will be the same at that moment, and the distance between A and B is 264 miles,  so, we can calculate the relative speed between them:

If the cars are moving towards each other the relative speed will be:

RelativeSpeed=FirstCarSpeed-(-SecondCarspeed)\\\\RelativeSpeed=x-(-x-14mph)=2x+14mph

Then, since we know that they covered a combined distance which is equal to 264 miles of distance in 2 hours + 45 minutes, we  have:

2hours+45minutes=120minutes+45minutes=165minutes\\\\\frac{165minutes*1hour}{60minutes}=2.75hours

Writing the equation, we have:

264miles=(2x+14mph)*t\\\\264miles=(2x+14mph)*2.75hours\\\\2x+14mph=\frac{264miles}{2.75hours}\\\\2x=96mph-14mph\\\\x=\frac{82mph}{2}=41mph

We have that the speed of the first car is equal to 41 mph.

Now, for the second car we have that:

SecondCarSpeed=FirstCarSpeed+14mph\\\\SecondCarSpeed=41mph+14mph=55mph

Hence, we have that:

FirstCarSpeed=41mph\\SecondCarSpeed=55mph

Have a nice day!

4 0
3 years ago
Read 2 more answers
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