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tatuchka [14]
3 years ago
10

Which of the following statements is​ correct? A. The relationship between two variables is linear whether it is represented by

a straight line or by a curved line. B. The relationship between two variables is nonlinear whether it is represented by a straight line or by a curved line. C. The relationship between two variables is linear when it is represented by a straight line and nonlinear when it is represented by a curved line. D. The relationship between two variables is linear when it is represented by a curved line and nonlinear when it is represented by a straight line.
Mathematics
1 answer:
LuckyWell [14K]3 years ago
6 0

Answer:

  C. The relationship between two variables is linear when it is represented by a straight line and nonlinear when it is represented by a curved line.

Step-by-step explanation:

The definition of "linear" is "related by a straight line". The definition of "non-linear" is "not related by a straight line." One simply needs to understand the definitions in order to choose the correct statement.

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How many, and what type of, solutions does 4x² + 12x + 9 = 0 have? 2 irrational solutions 1 rational solution 2 nonreal solution
SVEN [57.7K]

The discriminant is

\sqrt{ {12}^{2}  - 4(4)(9)}

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Show how to use substitution or elimination to solve the following system of equations. Write the solution as an ordered pair.
max2010maxim [7]

Answer:

  (4, 6)

Step-by-step explanation:

<u>Substitution</u>

Using the second equation, we can substitute for y in the first equation.

  4x -(2x-2) = 10

  2x +2 = 10 . . . . simplify

  x +1 = 5 . . . . . . .divide by 2

  x = 4 . . . . . . . . . subtract 1

  y = 2(4) -2) = 6 . . . . substitute for x in the equation for y

The solution is (x, y) = (4, 6).

__

<u>Elimination</u>

Often, we like to start with both equations in standard form when we solve by elimination. That is nice, but not completely necessary.

We can eliminate the y-variable by simply adding the two given equations.

  (4x -y) +(y) = (10) +(2x -2)

  4x = 8 + 2x . . . . . collect terms. The y-variable has been eliminated.

  2x = 8 . . . . . . . . . subtract 2x

  x = 4 . . . . . . . . . . divide by 2

Y can be found using the second equation.

  (x, y) = (4, 6)

__

We could have eliminated the x-variable by multiplying the second equation by 2, then adding the two equations.

  (4x -y) +2(y) = (10) +2(2x -2)

  y = 6 . . . . . . . . . subtract 4x from both sides. The x-variable has been eliminated.

Now, x can be found using either equation.

  6 = 2x -2 . . . substitute for y in the second equation

  3 = x - 1 . . . divide by 2

  x = 4 . . . . . add 1

  (x, y) = (4, 6)

3 0
3 years ago
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